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3 years ago

Which of the following is equivalent to x^2 y^2/xy^2 when y=Ø and x=Ø ?

1 answer:

4 0

Based in your question where as ask on which of the following is the equivalent to x^2/xy^2 when y=0 and z=0 and based on my calculation and understanding the possible outcome of your equation will just result to zero but the answer is i think all of them

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What is the solution for the system of equations {9x+8y=3 6x−12y=−11?

lions [1.4K]

Answer:

( - $\frac{1}{3}$ , $\frac{3}{4}$ )

Step-by-step explanation:

Given the 2 equations

9x + 8y = 3 → (1)

6x - 12y = - 11 → (2)

To eliminate the y- term multiply (1) by 1.5

13.5x + 12y = 4.5 → (3)

Add (2) and (3) term by term

(6x + 13.5x) + (- 12y + 12y) = (- 11 + 4.5)

19.5x = - 6.5 ( divide both sides by 19.5 )

x = $\frac{-6.5}{19.5}$ = - $\frac{1}{3}$

Substitute this value into either of the 2 equations and solve for y

Using (1), then

- 3 + 8y = 3 ( add 3 to both sides )

8y = 6 ( divide both sides by 8 )

y = $\frac{6}{8}$ = $\frac{3}{4}$

Solution is (- $\frac{1}{3}$ , $\frac{3}{4}$ )

6 0

2 years ago

Write the equation of the line that passes through the points (4, -3) and

vivado [14]

Answer:

y+3=-5(x-4)

Add 20 characters to explain the point

8 0

2 years ago

Gabriel wants to paint the model. How

enyata [817]

Answer:

<h2>The area of the base is 144 square inches.</h2><h2>The area of each triangular face is 66 square inches.</h2><h2>Grabiel needs 408 square inches of paint.</h2>

Step-by-step explanation:

The complete problem is attached.

Notice that the figure is a square pyramid, where its base dimensions are 12 inches by 12 inches, which represents an area of

$B=12 \times 12 = 144 \ in^{2}$

The slant height of the pyramid is 11 inches, which allow us to find the area of each triangle face

$A=\frac{1}{2}bh =\frac{1}{2}(12)(11)= 66 \ in^{2}$

But there are four triangle faces, so $A_{faces} =4(66)=264 \ in^{2}$ .

Therefore, the area of each triangular face is 66 square inches.

So, the total surface area would be the sum

$S=144+264=408 \ in^{2}$

Therefore, Gabriel needs 408 square inches to paint the whole model.

4 0

3 years ago

Figure ABCD is transformed to figure A prime B prime C prime D prime, as shown: A coordinate grid is shown from negative 5 to 0

Bess [88]

Answer:

i need this answer too

7 0

2 years ago

What is the interquartile range (IQR) of the following data set 17 16 21 15 25 22 18 23 17

Pepsi [2]

IQR = 6

First locate the median $Q_{2}$ at the centre of the data arranged in ascending order. Then locate the lower and upper quartiles $Q_{1}$ and $Q_{3}$ located at the centre of the data to the left and right of the median.