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mestny [16]
3 years ago
9

The residents of a city voted on wether to raise property taxes. The ratio of yes votes to no votes was 5 to 6. If there were 84

81 total votes, how many no votes were there?
Mathematics
1 answer:
Dafna1 [17]3 years ago
4 0

Answer:

The residents of a city voted on whether to raise property taxes. The ratio of yes votes to no votes was 4 to 7 . If there were 10,725 total votes .

Step-by-step explanation:

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If f(x) = 2x to the second power - 10, find f(5)
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F(5) = 2(5)^2 - 10
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Irene is cutting construction paper into rectangles for a project. She needs to cut one rectangle that is 8 inches × 13 1/2 inch
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A cylinder has a radius of 3.5. inches. what is the base area of the cylinder​
Aleks [24]

Answer:

The formula for area of a circle is A = tt r^2

So 3.14 * 3.5^2 = 38.5

Step-by-step explanation:

8 0
3 years ago
5
LekaFEV [45]

Answer: y-1=\dfrac32(x+3)

Step-by-step explanation:

Slope of a line passes through (a,b) and (c,d) = \dfrac{d-b}{c-a}

In graph(below) given line is passing through (-2,-4) and (2,2) .

Slope of the given line passing through (-2,-4) and (2,2) =\dfrac{-4-2}{-2-2}=\dfrac{-6}{-4}=\dfrac{3}{2}

Since parallel lines have equal slope . That means slope of the required line would be .

Equation of a line passing through (a,b) and has slope m is given by :_

(y-b)=m(x-a)

Then, Equation of a line passing through(-3, 1) and has slope =  is given by

(y-1)=\dfrac32(x-(-3))\\\\\Rightarrow\ y-1=\dfrac32(x+3)

Required equation: y-1=\dfrac32(x+3)

8 0
3 years ago
Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. We learned about the de
attashe74 [19]

The question is incomplete. Here is the complete question.

Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. we learned about the degree measure of an ac, but they also have physical lengths.

a) Determine the arc length to the nearest tenth of an inch.

b) Explain why the following proportion would solve for the length of AC below: \frac{x}{12\pi } = \frac{130}{360}

c) Solve the proportion in (b) to find the length of AC to the nearest tenth of an inch.

Note: The image in the attachment shows the arc to solve this question.

Answer: a) 9.4 in

c) x = 13.6 in

Step-by-step explanation:

a) \frac{arclength}{2\pi.r } = \frac{mAB}{360}, where:

r is the radius of the circumference

mAB is the angle of the arc

arc length = \frac{mAB.2.\pi.r }{360}

arc length = \frac{90.2.3.14.6}{360}

arc length = 9.4

The arc lenght for the image is 9.4 inches.

b) An <u>arc</u> <u>length</u> is a fraction of the circumference of a circle. To determine the arc length, the ratio of the length of an arc to the circumference is equal to the ratio of the measure of the arc to 360°. So, suppose the arc length is x, for the arc in (b):

\frac{x}{2.6.\pi } = \frac{130}{360}

\frac{x}{12\pi } = \frac{130}{360}

c) Resolving (b):

x = \frac{130.12.3.14}{360}

x = 13.6

The arc length for the image is 13.6 inches.

6 0
3 years ago
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