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Savatey [412]
4 years ago
7

You drive 1650 miles at 50 mph; how long will it take?

Mathematics
2 answers:
eduard4 years ago
6 0

Answer:

33 hours

Step-by-step explanation:

Take the distance and divide by the rate to get the time

1650/50 = the number of hours

33 hours

prohojiy [21]4 years ago
3 0

Answer:

33 hours

Step-by-step explanation:

mph stands for miles per hour

So, 1650/50=33, which finds how long in hours

So, if your speeds stays constant it should take 33 hours

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Suppose U= {1, 2, 3, 4, 5, 6, 7, 8} is the universal set and P= {1, 2, 3, 4}. What is P?
Digiron [165]
Did you mean P' ? The letter P with a tick mark after it. If so, then start with set U and erase any number you find in set P

We start with 
{1,2,3,4,5,6,7,8}
and we erase the following: 1,2,3,4
since those numbers are in set P

P = {1,2,3,4}
P ' = {5, 6, 7, 8}

<span>The set P' is the complement of set P. It is, in a sense, the opposite of set P. It contains everything that P doesn't have.</span>
4 0
3 years ago
Hi there can anyone up here that's is really good in math please help me with this question please
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6 0
4 years ago
Solve for x.
Mademuasel [1]

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A

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8 0
3 years ago
Write the point-slope form of the equation of the line passing through the points (-5, 6) and (0, 1).
Y_Kistochka [10]
The point slope form:
y - y_1 = m(x - x_1)

We need to find the slope. To find the slope we can use the following formula:
\frac{y_2 - y_1}{x_2 - X_1}

Use the points <span>(-5, 6) and (0, 1) and plug it into our slope formula and solve:
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So our slope is -1 which means m = slope = -1 
Now that we have our slope lets create the point slope form

Our point slope form equation is y - y_1 = m(x - x_1) Remember 
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First insert the m = slope = -1 number where m is located
y - y_1 = -1(x - x_1)

Next, insert the -5 from (-5,6) where x_1 is located and the 6 from (-5,6) where y_1 is located.
y - y_1 = -1(x - x_1)
y - 6 = -1(x - (-5))
Now simplify 
y - 6 = -1(x - (-5))
y - 6 = -1(x +5) <-------Answer





8 0
4 years ago
The unit of measure of an area equal to 1 km by 1m
scoundrel [369]
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