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Deffense [45]
3 years ago
10

Theo started to solve the quadratic equation (x + 2)^2 – 9 = –5. He added 9 to both sides and the resulting equation was (x + 2)

^2 = 4. Next, he took the square root of each side. Which was the resulting equation of that step?
x + 2 = ±4
x + 2 = ±2
x + 2 = ±8
x + 2 = ±16
Mathematics
2 answers:
Sliva [168]3 years ago
6 0
When we take the square root of each side, the equation would become:
abs (x+2) = 2
⇒ x+2 = <span>±2.

The final answer is </span><span>x + 2 = ±2.
</span>
Hope this helps~



Ugo [173]3 years ago
6 0

The square root of  (x + 2)²  is  (x + 2) .

The square roots of  4  are  +2  and  -2 .

So the resulting equation was            x + 2  =  <span>± 2 .

From there, it was pretty easy for Theo to find the solutions
to the original equation . . .

If  (x + 2) = +2 , then  x = 0 .

If  (x + 2) = -2 , then  x = -4 .

</span>
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How many times larger than (6 - 4) is (6 - 4) × 5?
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Answer:

5 times bigger

Step-by-step explanation:

(6-4) = 2

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2 years ago
Two accounts earn simple interest. The balance y (in dollars) of Account A after x years can be modeled by y=10x+500. Account B
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I know that real numbers consist of the natural or counting numbers, whole numbers, integers, rational numbers and irrational nu
ra1l [238]

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The set of real numbers, \mathbb R, is a subset of \mathbb C, where each number in \mathbb R can be obtained by taking b=0 and letting a be any real number.

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I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because 2=2+0i.

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3 0
3 years ago
System of equations how to for this problem?
MrMuchimi
Its 7y
 hope this helpeddd!
6 0
3 years ago
Solve for c : <br> 6/13=3/c
nexus9112 [7]
Cross mutiply and the answer would be 13/2 or 6.5
7 0
3 years ago
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