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Step2247 [10]
3 years ago
6

An initial investment of 480$ is appreciated for 2 years in an account that earns 7% interest, compound quarterly. Find the amou

nt of money in the account at the end of the period.
Mathematics
1 answer:
gtnhenbr [62]3 years ago
5 0

Answer:

The answer is $1,175.34

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NEED HELP ASAP!!! for geometry class
balandron [24]

Answer:

B) AAS

Step-by-step explanation:

B) AAS

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3 years ago
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Which graph represents the solution to the given system?<br> Y=-x+5<br> y= 1/4 x+10
jeka57 [31]

Answer:

See attachment

Step-by-step explanation:

The given system is :

y =  - x + 5

y =  \frac{1}{4}x + 10

Let us equate both equations and solve for x.

- x + 5 =  \frac{1}{4}x + 10

- 4x + 20 = x + 40

20 - 40 =x + 4x

- 20 = 5x

x =  - 4

y =  -  - 4 + 5 = 9

The the two lines of this system will meet at (-4,9)

The graph is shown in the attachment.

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3 years ago
What is the slope of the line through (-1,2) and (-3,-2)?​
Morgarella [4.7K]

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D

Step-by-step explanation:

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3 years ago
For selected years, the national health care expenditure, in billion of dollors can be modelled by H=29.57e^0.0970t, remains acu
Sliva [168]

Answer:

The correct answer is 54.76 years.

Step-by-step explanation:

The national health care expenditure (H) , in billion of dollars is modeled by

H = 29.57 × e^{0.0970t}.

To measure the time before which national health expenditure reach 6000 billion dollars.

Thus putting the value of H = 6000 in the above modeled equation we get,

⇒ 6000 = 29.57 × e^{0.0970t}

⇒ \frac{6000}{29.57} = e^{0.0970t}

⇒ 202.908 = e^{0.0970t}

Taking logarithm with the base of e (㏑) both sides we get,

⇒ ㏑ 202.908 = ㏑ e^{0.0970t}

⇒ ㏑ 202.908 = 0.0970 × t

⇒ 0.0970 × t = 5.312

⇒ t = \frac{5.312}{0.0970}

⇒ t = 54.76.

Thus the total time required before which national health expenditure reach 6000 billion dollars is 54.76 years.

3 0
3 years ago
10 The diagram shows a garden in the shape of a rectangle.
harkovskaia [24]
20 + 8x = 32
- 20
8x = 12
--      --
8       8

x = 3/2= 1 1/2
3 0
3 years ago
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