Let, the numbers = x,y
x+y= 24 1st eqn
x-y = 44 2nd eqn
24-y-y = 44
-2y = 44-24
y = 20/-2 = -10
substitute that in equation 1st x = 24+10 = 34
so, the numbers would be 34 & -10
OK, let's try with no figure. We have an isosceles triangle sides s,s, and b.
Opposite b is angle t.
Draw the altitude h to bisect t. We have two right triangles, legs b/2 and h, hypotenuse s. The angle opposite b/2 is t/2 so
sin(t/2) = (b/2)/s = b/2s
So we arrived at the first part,
b = 2s sin(t/2)
The area of a triangle with sides s,s and included angle t is
A = (1/2) s² sin t
Point J' would be located at (5,0)
Answer:
77
Step-by-step explanation:
HAV A GREAT DAY hope this helps
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