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sertanlavr [38]
2 years ago
8

The three straight paths, , , and , meet each other at three points, A, B, and C. How do these points of intersection differ fro

m each other? Explain the differences in terms of the angles that you see. Also look at the length of the side opposite each angle. What pattern do you see regarding the measurements? In what situation would all the points of intersection resemble one another? Modify the triangle in GeoGebra to help you with your answers
Mathematics
1 answer:
stiv31 [10]2 years ago
5 0

Answer:

Step-by-step explanation:

I am sort. I have no idea

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Simplify 4x+5/6x^2-x-12 subtract 5x/6x^2-x-12
neonofarm [45]
<span>4x+5/6x^2-x-12 - (5x/6x^2-x-12)
= (4x + 5 - 5x)/(</span>6x^2-x-12)
= (-x + 5) / (2x - 3)(3x +4)
<span>
answer

       -x + 5
---------------------
</span>  (2x - 3)(3x +4)
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3 years ago
Can someone solve this please 9g = 36
Goryan [66]
You divide 9 on both sides than it would be g=4
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3 years ago
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Simplify (12a5−6a−10a3)−(10a−2a5−14a4) . Write the answer in standard form
almond37 [142]

Answer:

=14a^5+14a^4-10a^3-16a

Step-by-step explanation:

\left(12a^5-6a-10a^3\right)-\left(10a-2a^5-14a^4\right)\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=12a^5-6a-10a^3-\left(10a-2a^5-14a^4\right)\\-\left(10a-2a^5-14a^4\right):\quad -10a+2a^5+14a^4\\-\left(10a-2a^5-14a^4\right)\\\mathrm{Distribute\:parentheses}\\=-\left(10a\right)-\left(-2a^5\right)-\left(-14a^4\right)\\Apply\:minus-plus\:rules\\-\left(-a\right)=a,\:\:\:-\left(a\right)=-a\\=-10a+2a^5+14a^4\\=12a^5-6a-10a^3-10a+2a^5+14a^4

\mathrm{Simplify}\:12a^5-6a-10a^3-10a+2a^5+14a^4:\quad 14a^5+14a^4-10a^3-16a12a^5-6a-10a^3-10a+2a^5+14a^4\\Group\:like\:terms\\=12a^5+2a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:12a^5+2a^5=14a^5\\=14a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:-6a-10a=-16a\\=14a^5+14a^4-10a^3-16a

4 0
2 years ago
Let L be a tangent line to the hyperbola x y = 2 at x = 9 . Find the area of the triangle bounded by L and the coordinate axes.
mafiozo [28]

Answer:

A = 4

Step-by-step explanation:

The equation of the slope of the tangent line L is obtained by deriving the equation of the hyperbola:

y = \frac{2}{x}

y'=-2\cdot x^{-2}

The numerical value of the slope is:

y' = -2 \cdot (9)^{-2}\\y' = -\frac{2}{81}

The component of the y-axis is:

y = \frac{2}{9}

Now, the tangent line has the following mathematical model:

y = m \cdot x + b

The value of the intercept is found by isolating it within the equation and replacing all known variables:

b = y - m \cdot x

b = \frac{2}{9}-(-\frac{2}{81} )\cdot (9)\\b = \frac{4}{9}

Thus, the tangent line is:

y = -\frac{2}{81}\cdot x + \frac{4}{9}

The vertical distance between a point of the tangent line and the origin is given by the intercept.

d_{y} = \frac{4}{9}

In order to find horizontal distance between a point of the tangent line and the origin, let equalize y to zero and clear x:

-\frac{2}{81}\cdot x + \frac{4}{9}=0

-\frac{2}{9}\cdot x + 4 = 0

x = 18

d_{x} = 18

The area of the triangle is computed by this formula:

A = \frac{1}{2}\cdot d_{x}\cdot d_{y}

A = \frac{1}{2}\cdot (18)\cdot (\frac{4}{9} )

A = 4

4 0
3 years ago
PLEASE HELP WITH 1-3 ILL MARK U THE BRAINLIEST
sammy [17]

Answer:

1:A(-6,-1) B(-14,0) C(-11,4)

2:D(6,-3) E(2,-3) F(3, -4.5) G(5, -4.5)

3:H(-4,1) I(-4, 6) J(0,6) K(0,1)

Step-by-step explanation:

Before we begin, lets define the transformations:

(x, y)

T(a, b) = (x+a, y +b)

Rxaxis = (x, -y)

Ryaxis = (-x, y)

r(180, 0) = (-x, -y)

D.5(1/2x, 1/2y)

R(-90, O) = (-y, x)

1. T. A(6,-1) B(14,0) C(11,4)

   Rx. A(6, 1) B(14,0) C(11,-4)

   r180 A(-6,-1) B(-14,0) C(-11,4)

2. Rx D(-12,-6) E(-4,-6) F(-6, -9) G(-10, -9)

   Ry D(12,-6) E(4,-6) F(6, -9) G(10, -9)

   D.5 D(6,-3) E(2,-3) F(3, -4.5) G(5, -4.5)

3. Rx=1 H(-1,2) I(4, 2) J(4,-2) K(-1,-2)

   T H(1,4) I(6, 4) J(6,0) K(1,0)

   r-90 H(-4,1) I(-4, 6) J(0,6) K(0,1)

4 0
3 years ago
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