Answer:
I think it is 1/2 because it goes up 1 over 2
The number of 0.4 liter glasses of water that will be poured in the pitcher is 13
From the information given, we are being told that a pitcher can hold a maximum amount of 5.2 liters of water.
If we are to use a 0.4 liter of glass to pour water in the pitcher, then the number of times we will use the glass to pour water in the pitcher can be estimated as:
Number of glass that can fill the pitcher = 5.2 liters/ 0.4 liters
= 13 glass
Learn more about solving word problems in mathematics here:
brainly.com/question/2121480?referrer=searchResults
Answer:
(a) ln(x) = 0
Then 0 < x < 1
(b) e^x > 2
Then ln2 < x < ∞
(a) ln(3x - 17) = 5
x = 55.1377197
ln(a + b) + ln(a - b) - 5ln(c)
= ln[(a² - b²)/c^5]
Step-by-step explanation:
First Part.
(a) ln(x) < 0
=> x < e^(0)
x < 1 ....................................(1)
But the logarithm of 0 is 1, and the logarithm of negative numbers are undefined, we can exclude the values of x ≤ 0.
In fact the values of x that satisfy this inequalities are between 0 and 1.
Therefore, we write:
0 < x < 1
(b) e^x > 2
This means x > ln2
and must be finite.
We write as:
ln2 < x < ∞
Second Part.
(a) ln(3x - 17) = 5
3x - 17 = e^5
3x = 17 + e^5
x = (1/3)(17 + e^5)
= 55.1377197
Third Part.
We need to write
ln(a + b) + ln(a - b) - 5ln(c)
as a single logarithm.
ln(a + b) + ln(a - b) - 5ln(c)
= ln(a + b) + ln(a - b) - ln(c^5)
= ln[(a + b)(a - b)/(c^5)]
= ln[(a² - b²)/c^5]
[9tan(θ) * 9cot(θ)] / 9sec(θ)
First cancel out the 9's:
tan(θ)cot(θ)/sec(θ)
Recall the following trig identities:
tan = sin/cos
cot = cos/sin
sec = 1/cos
Thus, we can rewrite the expression as:
[ (Sin(θ)/cos(θ)) *(cos(θ)/sin(θ)) ] / (1/cos(θ))
In the numerator, the sine's and cosine's cancel each other out:
1 / (1/cos(θ))
which we can rewrite as cos(θ).
Answer:X would be 2 so The answer is c
Step-by-step explanation:
