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3 years ago

Which is an exponential growth function?

Mathematics

1 answer:

Alex787 [66]3 years ago

5 0

A linear equation has the x multiplied by a number, while exponential function has the x as a power

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I only need help on number 9. Find the value of Y.

natima [27]

6y+40=10y-32
8=4y
Y=2

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2 years ago

I’ll mark you as brainliest!

Virty [35]

Answer:

Area of rectangle = l*b

11*9

I think it will help you.

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2 years ago

Read 2 more answers

Can somebody please help me

Agata [3.3K]

Answer: I think it’s D
Explanation:

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2 years ago

Hello guys I really need help is anyone available please and ty

kati45 [8]

Answer:

your right

Step-by-step explanation:

I think....

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3 years ago

A NASA spacecraft measures the rate R of at which atmospheric pressure on Mars decreases with altitude. The result at a certain

AysviL [449]

Answer:

$R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}$

Step-by-step explanation:

For this case we have the following value:

$R = 0.0498 \frac{Kpa}{Km}$

We can convert this first to $\frac{Kpa}{m}$ like this:

$R=0.0498 \frac{Kpa}{Km} *\frac{1km}{1000m}=0.0000498 \frac{Kpa}{m}$

Now we use the fact the the pressure is defined as $P =\frac{F}{A}$ , whre P is the pressure, F the force and A the area, so then $Kpa= \frac{KN}{m^2}$ and then we can replace this:

$R=0.0000498 \frac{KN}{m^3}$

Now from definition of work we know that $W= Fd$ where W is the work, F the force and d the distance, so then is equivalent $KN =\frac{KJ}{m}$

And if we replace this into the equation we got:

$R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}$

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3 years ago