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Mice21 [21]
3 years ago
6

From a population of 200 elements, the standard deviation is known to be 14. A sample of 49 elements is selected. It is determin

ed that the sample mean is 56. The standard error of the mean is _____. a. 2 b. greater than 2 c. 3 d. less than 2
Mathematics
1 answer:
jeka943 years ago
5 0

Answer:

a. 2

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Standard deviation is known to be 14.

This means that \sigma = 14

Sample of 49

This means that n = 49

The standard error of the mean is

s = \frac{\sigma}{\sqrt{n}} = \frac{14}{\sqrt{49}} = \frac{14}{7} = 2

So the correct answer is given by option a.

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Answer:

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Step-by-step explanation:

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3 years ago
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What is the product in lowest terms? 1/6 • 5/7
Pani-rosa [81]

Multiply the numerator together and the denominators together.

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4 0
3 years ago
Pulse rates (in beats per minute) were collected on a sample of 36 men. The five number summary for the data is as follows: Lo:
algol13

Answer:

27 men had a pulse rate between 56 & 100.  

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 36

Five number summary:

Lowest value: 56

Lower Quartile: 71

Median: 80

Upper Quartile: 100

Highest value: 140

We have to find the number of men that had a pulse rate between 56 & 100.

56 is the lowest value of data and 100 is the third quartile of data.

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6 0
3 years ago
Solve the following logarithmic equations.<br> log2(49x^2) = 4
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Answer:

x_{1} = \frac{4}{7} \\x_{2} = \frac{-4}{7} \\

Step-by-step explanation:

To solve this equation, one must apply the following logarithmic property:

if

log_{a}(b) = c\\

then

b= a^{c}

Applying it to the problem at hand:

2^{4} = 49x^{2} \\x^{2} = \frac{16}{49} \\x_{1} = \frac{4}{7} \\x_{2} = \frac{-4}{7} \\

The solutions to the problem are 4/7 and -4/7.

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Step-by-step explanation:

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