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Dafna11 [192]
3 years ago
5

Round 576.071 to the nearest tenths​

Mathematics
1 answer:
pentagon [3]3 years ago
8 0
The answer is 576.1 !
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The sim of three consecutive integers is -204. What is the largest integer?
nlexa [21]

Let the largest of the three integers be x. The next smaller one is x - 1, and the smallest is x - 2.

Now we add them and set the sum equal to -204.

x + x - 1 + x - 2 = -204

3x - 3 = -204

3x = -201

x = -67

Answer: The largest integer is -67.

4 0
4 years ago
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If Fred feeds 12 horses for two weeks with 25 bales of hay, how many bales of hay does he need to feed 15 horses for two weeks?​
Dvinal [7]

Answer:

He needs 31.25 bales of hay to feed 15 horses for two weeks

Step-by-step explanation:

This question can be solved using a rule of three.

25 bales of hay feed 12 horses. How many feed 15 horses?

12 horses - 25 bales of hay

15 horses - x bales of hay

12x = 25*15

x = \frac{25*15}{12}

x = 31.25

He needs 31.25 bales of hay to feed 15 horses for two weeks

7 0
3 years ago
The ratio of 36 salted eggs to 18 guest​
satela [25.4K]
The answer would be 36:18 and done
6 0
3 years ago
Read 2 more answers
Please help, i need to know the steps of solving this question
kkurt [141]

Answer:

Step-by-step explanation:

eq. of line through (-4,0) and (3,2) is

y-0=(2-0)/(3+4) (x+4)

y=2/7 (x+4)

or y=2/7 x+8/7

m1=2/7

b1=8/7

eq. of line through (-3,2) and (4,0) is

y-2=(0-2)/(4+3) (x+3)

y-2=-2/7(x+3)

y=-2/7 x-6/7 +2

or y=-2/7 x+8/7

m2=-2/7

b2=8/7

m1b2+m2b1

=\frac{2}{7} \times \frac{8}{7} +(-\frac{2}{7} ) \times \frac{8}{7} \\=\frac{16}{49} -\frac{16}{49} \\=0

6 0
4 years ago
Joshua can purchase tile at one store for $0.99 per tile but he he will have to rent a tile saw for $25. At another store he can
Debora [2.8K]

Answer:

The number of tile for which the cost is same route to nearest tile is 49 .

Step-by-step explanation:

Given as :

The cost which Joshua will pay for tile at one store = $ 0.99 per tile + $ 25 for tile saw

The  cost which Joshua will pay for tile at another store = $ 1.50 per tile only

Let The number of tile for which the cost is same route to nearest tile = n

So, According to question

$ 0.99 × number of tile + $ 25 = $ 1.50 × number of tile

or, $ 0.99 × n + $ 25 = $ 1.50 × n

or, $ 1.50 × n - $ 0.99 × n = $ 25

I.e 0.51 × n = $ 25

∴  n = \frac{25}{0.51}

I.e n = 49.01 ≈ 49

So, The number of tile for which the cost is same route to nearest tile = n = 49

Hence The number of tile for which the cost is same route to nearest tile is 49 . Answer

5 0
3 years ago
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