First we have to answers stand that speed is equivalent to the distance traveled in a certain time span. That is speed = distance/time. Conversely, time = distance/speed. We are asked to find the speed going home given, distance, total time and speed going to school. We can answer this equation by adding the time Aidan is spending going and coming back from school
t = (distance to school)/(speed to school) + (distance to home)/(speed to home)
1hour = (16)/(40) + (16)/(speed to home)
Speed to home = 26.67miles/hour
Actually, this is worth 13 points. not 25. thanks!
Answer:
I think the answer is $480
Step-by-step explanation:
(4/5)/100 *$60000
=$480
Answer:
Part A) BD = 6.5 cm
Part B) see explanation
Step-by-step explanation:
See the attached figure
Part A) Find the length of BD
ΔDAB is a right triangle at A, AB is 3.3cm , DA is 5.6cm
So, DB is the hypotenuse
Using Pythagorean equation:
DB = √(AD² + AB²) = √(3.3² + 5.6²) = √42.25 = 6.5 cm
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Part B) Show that angle BCD is 90°
Given: CD is 5.2cm , BC is 3.9cm and DB = 6.5 cm
So, CD² = 5.2² = 27.04
BC² = 3.9² = 15.21
DB² = 6.5² = 42.25
So, CD² + BC² = 27.04 + 15.21 = 42.25 = DB²
So, DB represent a hypotenuse at ΔBCD
So, the apposite angle of BD is a right angle
So, ∠BCD = 90°