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Mathematics

1 answer:

Degger [83]3 years ago

7 0

The correct answer is B

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Mrac [35]

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4 years ago

Juan and Raj cut up a banana to put on cereal. Juan puts 17 of the banana on his bowl of cereal, and Raj puts 25 of the banana

rusak2 [61]

<h3><u>Question:</u></h3>

Juan and raj cut up a banana to put on cereal. juan puts 1/7 of the banana on his bowl of cereal, and raj puts 2/5 of the banana on his bowl of cereal.

what fraction of the banana did juan and raj put on their cereal altogether?

a. 2/35 banana

b. 3/12 banana

c. 3/7 banana

d. 19/35 banana

<h3><u>Answer:</u></h3>

Juan and Raj altogether put 19/35 banana

<h3><u>Solution</u>:</h3>

Given that, Juan and Raj cut up a banana to put on cereal

$fraction\ of\ banana\ put\ by\ Juan = \frac{1}{7}\\\\fraction\ of\ banana\ put\ by\ Raj = \frac{2}{5}$

We have to find the fraction of banana put by Juan and Raj altogether

This means, we have to add both the fractions

$fraction\ of\ banana\ put\ altogether = fraction\ of\ banana\ put\ by\ Juan + fraction\ of\ banana\ put\ by\ Raj$

$fraction\ of\ banana\ put\ altogether = \frac{1}{7} + \frac{2}{5}\\\\\text{Cross multiply to simplify }\\\\fraction\ of\ banana\ put\ altogether = \frac{1 \times 5 + 2 \times 7}{7 \times 5}\\\\fraction\ of\ banana\ put\ altogether = \frac{5+14}{35}\\\\fraction\ of\ banana\ put\ altogether = \frac{19}{35}$