Let: eq 1:2x+5y=-55
eq 2:y=3x+6
by substituting eq 2 in eq 1 we get,
2x+5(3x+6)=-55
2x+15x+30+55=0
17x + 85=0
x=-85/17
x=-5
By substituting x value in eq 2,
we have,
y=3(-5)+6=-15+6=-9
-50m^4 n^7 = 10m^2n^7(-5m^2)<span>
and
40m^2 n^10 = 10</span>m^2 n^7(4n^3)
Answer: GCF = 10m^2 n^7
<h3> </h3><h2> F-{1} (x)= x/6 + 5/6</h2>
The magnitude of a vector has to do with the vector length that is used to show the initial and final position of the vector.
<h3>What is a Vector?</h3>
This refers to the quantity that has a magnitude and direction and can be used to show position.
Hence, we can see that the vector, magnitude, and the directional angle values are not given so a general overview was given.
Read more about vectors here:
brainly.com/question/25811261
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Answer:
A: 12/7
Step-by-step explanation:
