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hjlf
3 years ago
15

Find the number, if 5/7 of it is 15

Mathematics
2 answers:
Karolina [17]3 years ago
7 0
Hey there! :D

Divide 15 by the numerator so we can find 1/7.

15/5= 3

3*7= 21

The number is 21. 

I hope this helps!
~kaikers
WARRIOR [948]3 years ago
3 0
5/7x=15
x=15×7/5=21
The number is 21
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The volume of a cube is 125 cm^3. The area of a square is 64 cm^2. How does the lenghth of one edge of the cube compare to the l
anzhelika [568]

Answer:

One edge of the cube is 5 cm, one edge of the square is 8 cm, so the edge of the cube is 3 cm shorter than the edge of the square.

Step-by-step explanation:

<h3 /><h3>The volume of the cube is found by the formula </h3><h2>V = s³, </h2><h3>where s is the side length (called the edge in this problem)</h3><h3>Since V = 125 cm³, we can take the cube root of 125 to find the edge length.</h3><h3>The cube root of 125 is 5, ( 5³ = 125)</h3><h3>So the edge of the cube is 5 cm</h3><h3 /><h3>The are of a square is found by the formula </h3><h2>A = s² ,  </h2><h3>where s is the side length (called the edge in this problem) </h3><h3>Since A = 64 cm², we can take the square root of 64 to find the edge length.</h3><h3>The square root of 64 is 8  (8² = 84)</h3><h3>So the edge of the square is 8cm</h3><h3 /><h3>Comparing the two edges tells us that the edge of the cube is 3cm shorter than the edge of the square.</h3>
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If half of two acres was planted with green beans, the answer would be one acre
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Suppose that the functions r and a are defined for all real numbers x as follows. r(x)=2x-1 S(x)=5x write the expressions for (r
NeTakaya

\boxed{(r-s)(x)=-3x-1} \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x} \\ \\ \boxed{(r+s)(-2)=-15}

<h2>Explanation:</h2>

In this exercise, we have the following functions:

r(x)=2x-1 \\ \\ s(x)=5x

And they are defined for all real numbers x. So we have to write the following expressions:

First expression:

(r-s)(x)

That is, we subtract s(x) from r(x):

(r-s)(x)=2x-1-5x \\ \\ Combine \ like \ terms: \\ \\ (r-s)(x)=(2x-5x)-1 \\ \\ \boxed{(r-s)(x)=-3x-1}

Second expression:

(r\cdot s)(x)

That is, we get the product of s(x) and r(x):

(r\cdot s)(x)=(2x-1)(5x) \\ \\ By \ distributive \ property: \\ \\ (r\cdot s)(x)=(2x)(5x)-(1)(5x) \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x}

Third expression:

Here we need to evaluate:

(r+s)(-2)

First of all, we find the sum of functions r(x) and s(x):

(r+s)(x)=2x-1+5x \\ \\ Combine \ like \ terms: \\ \\ (r+s)(x)=(2x+5x)-1 \\ \\ (r+s)(x)=7x-1

Finally, substituting x = -2:

(r+s)(-2)=7(-2)-1 \\ \\ (r+s)(-2)=-14-1 \\ \\ \boxed{(r+s)(-2)=-15}

<h2>Learn more: </h2>

Parabola: brainly.com/question/12178203

#LearnWithBrainly

5 0
3 years ago
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