This question wants you to find a common denominator for the fractions.
This means finding the LCM, least common multiple, for 21 and 9.
This can be done by listing the multiples for each number until they meet at a common one.
9:
9
18
27
36
45
54
63
21:
21
42
63
This means the LCM of 21 and 9 is 63.
So the lowest possible common denominator is 63.
21 • 3 = 63
So you have to multiply the numerator of 2/21 by 3 as well.
2 • 3 = 6
2/21 = 6/63
Now do the same for 1/9.
9 • 7 = 63
Multiply the numerator, 1, by 7.
1 • 7 = 7
1/9 = 7/63
So in the first blanks, you would put 6/63 for what 2/21 is equal to and 7/63 for what 1/9 is equal to.
7/63 is greater than 6/63.
7/63 > 6/63
That means 1/9 > 2/21
So 2/21 < 1/9 is the answer to the last blank.
Hope this helps!
The slope is 3, you can find by picking 2 points and do the rise divided by run
Answer:
2:25pm
Step-by-step explanation:
The time given is 5pm to catch the train back to school;
Amount of time for the tour = 1hr 45min
= 105min
Amount of time at gift shop = 30min
Amount of time to save = 20min
Total time = 105min + 30min + 20min = 155min
So;
Total time = 2hr 35min
So;
5pm - 2hr 35min = 2:25pm
Answer:
the probability that a code word contains exactly one zero is 0.0064 (0.64%)
Step-by-step explanation:
Since each bit is independent from the others , then the random variable X= number of 0 s in the code word follows a binomial distribution, where
p(X)= n!/((n-x)!*x!*p^x*(1-p)^(n-x)
where
n= number of independent bits=5
x= number of 0 s
p= probability that a bit is 0 = 0.8
then for x=1
p(1) = n*p*(1-p)^(n-1) = 5*0.8*0.2^4 = 0.0064 (0.64%)
therefore the probability that a code word contains exactly one zero is 0.0064 (0.64%)
