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lianna [129]
3 years ago
13

−6 2/1 −(−2 8/1 )+3 3/2

Mathematics
2 answers:
Andrews [41]3 years ago
5 0

Answer: 6 1/2

Step-by-step explanation:

-6 2/1 - (-2 8/1 ) + 3 3/2

-8 - (-10) + 4 1/2

-8 + 10 + 4 1/2

2 + 4 1/2

6 1/2

I didn't really understand some stuff but I think I did this right.. hope this helps!

mars1129 [50]3 years ago
4 0

Answer:

simplify the expression.

Exact Form:

13/2

Decimal Form:

6.5

Mixed Number Form:

6 1/2

Step-by-step explanation:

plz give me brainlyest

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If ΔP′QR′ is a dilated image of ΔPQR, find the scale factor (k) and then find the value of x. answers: A) 7 B) 10.7 C) 6 D) 73.5
Black_prince [1.1K]

Answer:

see explanation

Step-by-step explanation:

To find k, calculate the ratio of corresponding sides, image to original, that is

k = \frac{P'R'}{PR} = \frac{8}{28} = \frac{2}{7}

Thus

QR' = \frac{2}{7} × QR = \frac{2}{7} × 21 = 2 × 3 = 6 , that is

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Suppose we have a binomial experiment with n= 40 trials and a probability of success p= 0.50.Is it appropriate to use a normal a
exis [7]

Answer:

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It is not unusual to have 23 or more successes. The probabiltity of this event happening is 13.4%.

Step-by-step explanation:

To approximate the binomial distribution to a normal distribution, we can calculate n*p and n*q and if both are bigger than 5 we can do the approximation.

n*p=n*q=0.5*40=20

We can approximate to normal.

The parameters of the approximate normal distribution are:

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The continuity correction factor is used because the binomial is a discrete function and the normal a continous function.

The probability of 23 successes must be expressed in the normal distribution as:

P_B(r>23)=P_N(r>23+0.5)=P_N(r>23.5)\\\\z=(23.5-20)/3.16=1.1076\\\\P(r>23.5)=P(z>1.1076)=0.134\\\\P_B(r>23)\approx 0.314

It is not unusual to have 23 or more successes. The probabiltity of this event happening is 13.4%.

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