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uranmaximum [27]
3 years ago
8

I have a mix of 12 nickels and dimes in my pocket. All together I have $1 . How many nickles and dimes do I have?

Mathematics
1 answer:
fenix001 [56]3 years ago
8 0

Answer:

Step-by-step explanation:

n + d = 12

0.05n + 0.1d = 1    ║ × ( - 10 )

n + d = 12 ..... <em>(1)</em>

- 0.5n - d = - 10 ..... <em>(2)</em>

<em>(1)</em> + <em>(2)</em>

0.5n = 2 ⇒ n = 4

d = 12 - 4 = 8

There are <em>4 nickels</em> and <em>8 dimes</em> in the pocket.

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Can you solve 27,28,39,30,31,32,33,34?
kozerog [31]

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27. x^7

28. 4x^13

29. 1/f^4

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32. (4y^3 x^2)^2

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Step-by-step explanation:

27. \:  \:  \frac{ {x}^{ - 1} }{ {x}^{ - 8} }  \\  \frac{ {x}^{8} }{ {x}^{1} }  \\  {x}^{8 - 1}   =  {x}^{7} \\

28. \:  \:  \:  \frac{ {52x}^{6} }{ {13x}^{ - 7} }  \\   \frac{ {52x}^{6}  {x}^{7} }{13}  \\  {4x}^{6 + 7}  =  {4x}^{13}

29. \:  \: {f}^{ - 3} ( {f}^{2} )( {f}^{ - 3} ) \\  {f}^{( - 3) +2 + ( - 3) }  \\  {f}^{ - 4}  \\  \frac{1}{ {f}^{4} }  \\

30. \:  \: \frac{ {x}^{ - 4} }{ {x}^{ - 9} } \\   \frac{ {x}^{9} }{ {x}^{4} }  \\  {x}^{9 - 4}  =  {x}^{5}

31. \:  \:  \frac{ {24x}^{6} }{ {12x}^{ - 8} }  \\  \frac{ {24x}^{6} {x}^{8}  }{12}  \\  {2x}^{6 + 8}  =  {2x}^{14}  \\

32. \:  \:  \frac{ {3x}^{2}  {y}^{ - 3} }{ {12x}^{6}  {y}^{3} }  \\  \frac{ {3x}^{2} }{ {12x}^{6} {y}^{3}  {y}^{3}  }  \\  \frac{ {x}^{2 - 6} }{ {4y}^{3 + 3} }  \\  \frac{ {x}^{ - 4} }{ {4y}^{6} }  \\  \frac{1}{ {4y}^{6}  {x}^{4} }  = \frac{1}{({ {4y}^{3} {x}^{2} ) }^{2} }

33. \:  \:  {( {2x}^{3}  {y}^{ - 3}) }^{ - 2}  \\ {2x}^{3 \times  - 2}  {y}^{ - 3 \times  - 2}  \\  {2x}^{ - 6}  {y}^{6}  \\  \frac{ {2y}^{6} }{ {x}^{6} }  \\  {( \frac{2y}{x} )}^{6} \\

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2 years ago
10xy(4xy^3-7xy+9y^2)
Thepotemich [5.8K]

Answer:

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Step-by-step explanation:

10xy(4xy^{3} -7xy+9y^2)  

1. 10xy · 4xy^3 = 40x^2y^4

2. 10xy · -7xy = -70x^{2} y^{2}

3. 10xy · 9y^2 = 90xy^3

Final step: add up all of those values together to make an equation!

Answer:  40x^2y^4+ -70x^2y^2+ 90xy^3

Final Answer: 40x^2y^4-70x^2y^2+90xy^3

3 0
3 years ago
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