4. PLEASE HELP ME WITH THIS MATH HOMEWORK

Use the work shown below to write the equation for a line that passes through the points (−5, 0) and (−1, −8). 1. Use slope form

atroni [7]

Answer:

Step-by-step explanation:

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have two points (-5, 0) and (-1, -8). Substitute:

$m=\dfrac{-8-0}{-1-(-5)}=\dfrac{-8}{4}=-2$

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercpet

Put the value of the slope and coordinates of the point (-5, 0) to the equation of a line:

$0=-2(-5)+b$

$0=10+b$ <em>subtract 10 from both sides</em>

$-10=b\to b=-10$

Finally:

$y=-2x-10$

3 0

2 years ago

Read 2 more answers

The graph of the function f(x)=x^2-6x shifted 2 units to the left on the graph of g(x). Select the two functions that represent

Nimfa-mama [501]

The correct answer is

g(x) =f(x+2)
And

g(x)=x^2-2x-8

8 0

2 years ago

A number is divided by 6.then 8 is added Mto the quotient. Next3 is subtracted from the sum.the result is 7. What is the number?

hjlf

(n/6 + 8) - 3 = 7

(n/6 + 8) - 3 + 3 = 7 + 3

n/6 + 8 - 8 = 10 - 8

n/6 = 2

(n/6)(6) = 2(6)

n = 12

6 0

2 years ago

Problem PageQuestion Calcium levels in people are normally distributed with a mean of mg/dL and a standard deviation of mg/dL. I

SIZIF [17.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The calcium level that is the borderline between low calcium levels and those not considered low is $c = 8.68$

Step-by-step explanation:

From the question we are told that

The mean is $\mu = 9.5\ mg/dL$

The standard deviation $\sigma = 0.5 \ mg/dL$

The proportion of the population with low calcium level is $p =$ 5% = 0.05

Let X be a X random calcium level

Now the P(X < c) = 0.05

Here P denotes probability

c is population with calcium level at the borderline

Since the calcium level is normally distributed the z-value is evaluated as

$P(Z < \frac{c - \mu}{\sigma } ) = 0.05$

The critical value for 0.05 from the standard normal distribution table is

$t_{0.05} = -1.645$

=> $\frac{c - \mu}{\sigma } = -1.645$

substituting values

$\frac{c - 9.5}{0.5 } = -1.645$

=> $c - 9.5 = -0.8225$

=> $c = 8.68$

6 0

3 years ago

Adam is training a group of cyclists. Each cyclist completes a 10-kilometer time trial during training. Adam records the times,

nydimaria [60]

The histogram which shows the results of the time trial is option B

<h3>Histogram</h3>

Given data:

12:32, 12:46, 13:30, 15:03, 13:43, 13:46, 14:20, 14:29, 12:34, 14:43, 15:26, 16:02, 16:16, 14:38, 16:55, 17:10, 14:26, 17:21, 17:58, 13:30

Grouping of data,:

12:00 - 12:59 = 3

13:00 - 13:59 = 4

14:00 - 14:59 = 5

15:00 - 15:59 = 2

16:00 - 16:59 = 3

17:00 - 17:59 = 3

The frequency is represented on the y-axis(number of cyclist)
The time is represented on the x-axis

Learn more about histogram:

brainly.com/question/9388601

#SPJ1

7 0

1 year ago