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3 years ago

How do you name a ray?

Mathematics

2 answers:

ivolga24 [154]3 years ago

6 0

Answer:

By two points.

In the figure at the top of the page, the ray would be called AB because starts at point A and passes through B on its way to infinity. Recall that points are usually labelled with single upper-case (capital) letters

Step-by-step explanation:

Assoli18 [71]3 years ago

4 0

Answer:

By two points.

Step-by-step explanation:

You might be interested in

What is the area of this trapezoid?

Ivanshal [37]

Answer: 357 cm²

Step-by-step explanation: In this problem, were asked to find the area of the trapezoid shown. Remember that a trapezoid is a quadrilateral with one pair of parallel sides. The formula for the area of a trapezoid is shown below

The b's are the bases or the parallel sides and the h represents the height.

So in the trapezoid shown, the bases are 15 cm and 27 cm and the height is 17 cm.

Plugging this information into the formula, we have .

Next, the order of operations tells us that we must simplify inside the parentheses first. 15 cm + 27 cm is 42 cm and we have

1/2 × 42 cm is 21 cm and we have (21 cm)(17 cm) which is 357 cm².

So the area of the trapezoid shown is 357 cm².

5 0

3 years ago

Help! What’s the y intercept of the linear equation 7+y=4.3x

Rasek [7]

Answer:

(0,-7)

Step-by-step explanation:

the y-intercept is found when the x-value is equal to 0. In this case, we are finding a coordinate pair. First, plug in 0 for x.

7+y=4.3(0)

simplify

7+y=0

subtract 7 from both sides

y=-7

Make it an ordered pair,

(0,-7)

8 0

3 years ago

Suppose f(x) - x = 2/ x. Fincd f(- 3)

myrzilka [38]

Answer:

To find the mode you need to check the number which is more often repeated in the set than the other.But as you can see here there is no number which is repeated more often than the other everyone is repeated once,so in this case we say that the set of data values has no mode.

To find the the range of the set of data you need to first place the numbers in ascending order (as it is already in) and then find the greatest and the smallest number and subtract them.

Range :

10,20,30,40,50,60,70,80,90,100,110,120,130,140,150.

Greatest number = 150.

Smallest number = 10.

Subtract = 150-10 = 140.

Step-by-step explanation:

6 0

3 years ago

Two numbers multiply to be -7 and add to be -6. What are the numbers? Example; 2,3

rewona [7]

Given:

Let the two numbers be x and y.

Two numbers multiply to be -7 and add to be -6.

This can be written in equation as,

$xy=-7$ and

$x+y=-6$

Value of the two numbers:

Let us determine the value of the two numbers using substitution method.

Substituting $y=-6-x$ in the equation $xy=-7$ , we get;

$x(-6-x)=-7$

Simplifying, we get;

$-6x-x^2=-7$

$x^2+6x-7=0$

$(x+7)(x-1)=0$

$x=-7, 1$

Thus, the values of x are x = 1,-7

When x = 1 , the equation $x+y=-6$ becomes $y=-7$

When x = -7, the equation $x+y=-6$ becomes $y=1$

Therefore, the two numbers are 1 and -7

3 0

3 years ago

You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confide

FrozenT [24]

Question:

You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of $114.00. Assume the population standard deviation is $15.30. Construct a 90% confidence interval for the population mean.

Answer:

At the 90% confidence level, confidence interval = 110.2484 < μ < 117.7516

At the 95% confidence level, confidence interval = 109.53 < μ < 118.48

The 95% confidence interval is wider

Step-by-step explanation:

Here, we have

Sample size, n = 45

Sample mean, $\bar x$ = $114.00

Population standard deviation, σ = $15.30

The formula for Confidence Interval, CI is given by the following relation;

$CI=\bar{x}\pm z\frac{\sigma}{\sqrt{n}}$

Where, z is found for the 90% confidence level as ±1.645

Plugging in the values, we have;

$CI=114\pm 1.645 \times \frac{15.3}{\sqrt{45}}$

or CI: 110.2484 < μ < 117.7516

At 95% confidence level, we have our z value given as z = ±1.96

From which we have $CI=114\pm 1.96 \times \frac{15.3}{\sqrt{45}}$

Hence CI: 109.53 < μ < 118.48

To find the wider interval, we subtract their minimum from the maximum as follows;

90% Confidence level: 117.7516 - 110.2484 = 7.5

95% Confidence level: 118.47503 - 109.5297 = 8.94

Therefore, the 95% confidence interval is wider.

8 0

3 years ago

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