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3 years ago

How do you name a ray?

Mathematics

2 answers:

ivolga24 [154]3 years ago

6 0

Answer:

By two points.

In the figure at the top of the page, the ray would be called AB because starts at point A and passes through B on its way to infinity. Recall that points are usually labelled with single upper-case (capital) letters

Step-by-step explanation:

Assoli18 [71]3 years ago

4 0

Answer:

By two points.

Step-by-step explanation:

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. The ratio of a circumference to diameter is

Goryan [66]

One of the most fundamental truths of (Euclidean) geometry is that the ratio of the circumference to the diameter of any circle is a constant, and that constant is called pi (denoted by π π). Let C be the (length of the) circumference of a circle, and let d be its diameter. Then, we must have: C d = π C d = π

5 0

3 years ago

Alicia drew a map of Texas. In the scale Alicia used for the map, .50 inch represents 20 miles. What is the distance between two

kramer

Answer:

An actual distance of 360 miles correspond to 9 inches on the map

Step-by-step explanation:

From the question, we have a scale of 0.5 inches representing 20 miles

Now, we want to relate an actual distance of 360 miles to a measurement on the map using the scale

From here, we have that;

0.5 inches = 20 miles

x inches = 360 miles

x * 20 = 0.5 * 360

20x = 180

x = 180/20

x = 9 inches

6 0

3 years ago

Read 2 more answers

Plss hellpppp thank uu

Leviafan [203]

The top row on the right:)

this number line includes any number to the left of 6 including 6!

4 0

3 years ago

Read 2 more answers

Use the arc length formula to find the length of the curve y = 4x − 5, −1 ≤ x ≤ 2. check your answer by noting that the curve is

professor190 [17]

Ok, here we go. Pay attention. The formula for the arc length is $AL= \int\limits^b_a { \sqrt{1+( \frac{dy}{dx})^2 } } \, dx$ . That means that to use that formula we have to find the derivative of the function and square it. Our function is y = 4x-5, so y'=4. Our formula now, filled in accordingly, is $AL= \int\limits^2_1 { \sqrt{1+4^2} } \, dx$ (that 1 is supposed to be negative; not sure if it is til I post the final answer). After the simplification we have the integral from -1 to 2 of $\sqrt{17}$ . Integrating that we have $AL= \sqrt{17}x$ from -1 to 2. $2 \sqrt{17}-(-1 \sqrt{17} )$ gives us $3 \sqrt{17}$ . Now we need to do the distance formula with this. But we need 2 coordinates for that. Our bounds are x=-1 and x=2. We will fill those x values in to the function and solve for y. When x = -1, y=4(-1)-5 and y = -9. So the point is (-1, -9). Doing the same with x = 2, y=4(2)-5 and y = 3. So the point is (2, 3). Use those in the distance formula accordingly: $d= \sqrt{(2-(-1))^2+(3-(-9))^2}$ which simplifies to $d= \sqrt{9+144}= \sqrt{153}$ . The square root of 153 can be simplified into the square root of 9*17. Pulling out the perfect square of 9 as a 3 leaves us with $3 \sqrt{17}$ . And there you go!

5 0

3 years ago

Use complete sentences to describe the transformation that maps ABCD onto its image.

Lapatulllka [165]

General Idea:

When a point or figure on a coordinate plane is moved by sliding it to the right or left or up or down, the movement is called a translation.

Say a point P(x, y) moves up or down ' k ' units, then we can represent that transformation by adding or subtracting respectively 'k' unit to the y-coordinate of the point P.

In the same way if P(x, y) moves right or left ' h ' units, then we can represent that transformation by adding or subtracting respectively 'h' units to the x-coordinate.

P(x, y) becomes $P'(x\pm h, y\pm k)$ . We need to use ' + ' sign for 'up' or 'right' translation and use ' - ' sign for ' down' or 'left' translation.

Applying the concept:

The point A of Pre-image is (0, 0). And the point A' of image after translation is (5, 2). We can notice that all the points from the pre-image moves 'UP' 2 units and 'RIGHT' 5 units.

Conclusion:

The transformation that maps ABCD onto its image is translation given by (x + 5, y + 2),

In other words, we can say ABCD is translated 5 units RIGHT and 2 units UP to get to A'B'C'D'.

6 0

3 years ago