Question

How many blocks with dimensions of One-third times 1 times 1 can fit in a unit cube?

Answer 1

Given:

Dimensions of a block are $\dfrac{1}{3}\times 1\times 1$.

To find:

The number of block that can be fit in a unit cube.

Solution:

Volume of a cuboid is:

$V=l\times b\times h$

Where, l is length, b is breadth or width and h is the height of the cuboid.

So, the volume of the given block is:

$V_1=\dfrac{1}{3}\times 1\times 1$

$V_1=\dfrac{1}{3}$

Dimensions of a unit cube are $1\times 1\times 1$. So, the volume of the unit cube is:

$V_2=1\times 1\times 1$

$V_2=1$

We need to divide the volume of unit cube by the volume of a block to find the number of block that can be fit in a unit cube.

So, the number of blocks that fit in a unit cube is:

$n=\dfrac{V_2}{V_1}$

$n=\dfrac{1}{\dfrac{1}{3}}$

$n=3$

Therefore, the correct option is B.

Answer 2

Answer:

the answer would be "b" 3 because its in 1/3 and the block is 1/3