Question

Please answer fast, it's important... Q) find the volume of cube whose dimensions are (x+7y), (7x-y) and (xy-5).​

Answer 1

Answer:

$Volume = 7x^3y+48x^2y^2-7xy^3 -35x^2-240xy-35y^2$

Step-by-step explanation:

Given

Shape: Cube

Dimension: (x+7y), (7x-y) and (xy-5).​

Required

Determine the volume

The volume is calculated by multiplying the dimensions:

$Volume = (x+7y) * (7x-y) * (xy-5)$

Evaluate the first 2 brackets

$Volume = [x(7x-y)+7y(7x-y)] * (xy-5)$

$Volume = [(7x^2-xy)+(49xy-7y^2)] * (xy-5)$

$Volume = [7x^2-xy+49xy-7y^2] * (xy-5)$

$Volume = [7x^2+48xy-7y^2] * (xy-5)$

Open brackets

$Volume = xy[7x^2+48xy-7y^2] -5[7x^2+48xy-7y^2]$

$Volume = 7x^3y+48x^2y^2-7xy^3 -35x^2-240xy-35y^2$