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Westkost [7]
3 years ago
14

25 dollars as an interger

Mathematics
2 answers:
strojnjashka [21]3 years ago
5 0

Answer:

-25

Step-by-step explanation:

Hope this helps! :)

shutvik [7]3 years ago
4 0

Answer:

25

Step-by-step explanation:

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mart [117]

Answer:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

tep-by-step explanation:

In order to find the integral:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx

we can do the following substitution:

Let's call

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which allows us to do convert the original integral into a much simpler one of easy solution:

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Therefore, our integral written in terms of "x" would be:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

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3 years ago
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