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castortr0y [4]
3 years ago
12

Miguel divided 205 oranges evenly into 5 boxes. How many oranges were in each box?

Mathematics
2 answers:
dexar [7]3 years ago
8 0

Answer:

41

Step-by-step explanation:

205 divided by 5=41

Snezhnost [94]3 years ago
5 0

Answer:

The Answer is 41 oranges in each box

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Simplify the polynomial (-8×)+×+(-2×)
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(-8x)+x+(-2x) 
-7x+(-2x)
-9x
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When constructing inscribed polygons and parallel lines how are these steps different
Sever21 [200]

When constructing inscribed polygons and parallel lines, the steps are different as a compass is used to copy an angle.

 

A compass<span> is an instrument used for navigation and orientation that shows direction relative to the geographic "cardinal directions", or "points".</span>

3 0
3 years ago
The vertices of a rectangle are (1, -3), (4,0), (0,4) and (-3,1). What is the area of the rectangle? ​
motikmotik

Answer:

48

Step-by-step explanation:

You can use a graphing calculator like desmos or draw your own graph to figure this out. Start by graphing each of those points. Then count the width and height. Multiply them to get the area. The width and height of the rectangle were 6 and 8, so the area is 48

3 0
3 years ago
5/6+5/12 <br><br> For brainliest
Amiraneli [1.4K]

Answer:

5/4

Step-by-step explanation:

5/6+5/12

or, {(5×2)+5}/12

or, 15/12 = 5/4

8 0
3 years ago
Read 2 more answers
A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6. Find the total area of the pyramid.
Tanzania [10]

The total area of pyramid is 113.569 square units

The equation to find the total area of the pyramid is Total area = base area + lateral area.

<u>Solution:</u>

Given, A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6.

<em><u>The total area of pyramid is given by:</u></em>

A=A_{b}+A_{l}   ---- eqn 1

Where,

A_{b} \text { is the base area and } A_{l} \text { is the lateral area }

<em><u>The area of base is given as:</u></em>

A_{b}=\frac{3 \sqrt{3}}{2} l^{2}

Where "l" is the side of hexagon.

Substituting we get,

\begin{array}{l}{A_{b}=\frac{3 \sqrt{3}}{2}(4)^{2}} \\\\ {=\frac{3 \sqrt{3}}{2} \times 16=3 \sqrt{3} \times 8} \\\\ {A_{b}=24 \sqrt{3}}\end{array}

<em><u>The lateral area is given as:</u></em>

A_{l}=3 b h

Where,

b: base of the triangle

h: height of the triangle

Substituting we get,

\begin{array}{l}{A_{l}=3 \times(4) \times(6)} \\\\ {A_{l}=72}\end{array}

Plugging in the values we found in eqn 1 we get,

A=24 \sqrt{3}+72

A = 113.569 square units

<em><u>Summarizing the results:</u></em>

The total area of pyramid is 113.569 square units approximately

The equation used to find total area of pyramid is Total area = base area + lateral area.

8 0
3 years ago
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