Answer:
dunno
Step-by-step explanation:
hope this helps has hdhd
Complete Question
A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set was split into 5 segments (each 6.4 seconds long), what is the resulting:
a)F minimum
b) F maximum
c) Frequency resolution
Answer:
a) 
b) 
c) 
Step-by-step explanation:
From the question we are told that:
Time 
Frequency
Segments 
Generally the equation for Frequency Range is mathematically given by


Therefore
a) 
b) 
c)
Generally the equation for Frequency Resolution is mathematically given by

Where
N=The Total dat points
N=Sampling Frequency *Time


Therefore


Negative , you always put the biggest numbers value at the end
Answer:
f(x) = + cosx or - cosx
Step-by-step explanation:
(2+tan^2x/sec^2x) -1 =(f(x))^2
=(( 1 + sec^2x)/sec^2x) -1
= 1 / sec^2x + 1 - 1
= 1 / sec^2x
= cos^2x
(f(x))^2 = cos^2x
f(x) = + cosx or - cosx
Answer:
see explanation
Step-by-step explanation:
Given
+ 2c + 11
=
-
+ 2c + 11
= 3c - 1 + 2c + 11
= 5c + 10
(b)
We have the expression
5c + 10 ← factor out 5 from each term
= 5(c + 2)