Answer: x1 = 0; x2 = 5/3; x3 = 1/3
x1 + 2x2 - x3 = 3 => 2x1 + 4x2 - 2x3 = 6
2x1 + x2 - 2x3 = 1
=> 4x2 - x2 = 5
⇔ 3x2 = 5
⇔ x2 = 5/3
with x2 = 5/3, we have: x1 - x3 = 3 - 10/3 = -1/3
3x1 - 5x3 = 5 - 4.5/3 = -5/3
=> x1 = 0
x3 = 1/3
Step-by-step explanation:
Answer:
2806.33333333
Step-by-step explanation:
Given:
The equation is:

To find:
The error in the given equation and correct it.
Solution:
We have,

Taking left-hand side, we get

![[\because a^2-b^2=(a-b)(a+b)]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D)
![[\because (ab)^x=a^xb^x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28ab%29%5Ex%3Da%5Exb%5Ex%5D)

It is not equal to right-hand side
. In the right hand side, there must be a negative sign instead of positive sign.
Therefore,
.
Answer:
Carlos is incorrect.
Step-by-step explanation:
We have been given that a line through the origin has a slope of
. Carlos thinks the slope of a perpendicular line at the origin will be 3.
We know that the slope of a perpendicular line to a given line is always negative reciprocal of the slope of the given line.
The slope of the perpendicular line at the origin will be negative reciprocal of
.
Let us find negative reciprocal of
as:

Since the slope of a perpendicular line at the origin is
, therefore, Carlos is incorrect.
Answer:
(-4,3)
Step-by-step explanation: