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NeX [460]
3 years ago
8

Someone talk to me bout anythang

Mathematics
1 answer:
enot [183]3 years ago
7 0

Answer:

do you think pineapple belongs on pizza ?

Step-by-step explanation:

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SOLVE
Sauron [17]

Answer:

approximately

1623.6

Step-by-step explanation:

16 1/2%=.165 which is approximately equal to 1/6, so we can just multiply the original number by 6.

7 0
3 years ago
Circumference of a circle of radius 13.4cm
Sedbober [7]

Answer:

26.8 pi or approx. 84.19

Step-by-step explanation:

Circumference can be found by multiplying the diameter by pi. The diameter is twice the radius, which in this case is 13.4, so it's 13.4 * 2 = 26.8.

Multiply by pi, and you've got your answer!

5 0
3 years ago
(3,y) (1,4) m= -2 what is the value of y if the line through the two given points is to have indicated slope
riadik2000 [5.3K]

Answer:

y=0

Step-by-step explanation:

The equation for the slope is

m = ( y2-y1)/(x2-x1)

-2 = (4-y)/(1-3)

-2 = (4-y)/-2

Multiply each side by -2

4 = 4-y

Subtract 4 from each side

4-4 = 4-y-4

0 = -y

0=y

5 0
3 years ago
Which point on the scatter plot is an outlier?
dlinn [17]

Answer:

The point 9,50

Step-by-step explanation:

All the other ones are within a reasonable distance of each other.

7 0
2 years ago
Where should the point P be chosen on line segment AB so as to maximize the angle θ? (Assume a = 4 units, b = 5 units, and c = 9
taurus [48]
From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.

Using pythagoras theorem,
\tan M= \frac{a}{b-x} \\ \\ M=\tan^{-1}\left(\frac{a}{b-x}\right)
and
\tan N= \frac{c}{x} \\ \\ N=\tan^{-1}\left(\frac{c}{x}\right)

Angle θ is given by
\theta=180-M-N \\  \\ =180-\tan^{-1}\left(\frac{a}{b-x}\right)-\tan^{-1}\left(\frac{c}{x}\right)

Given that a = 4 units, b = 5 units, and c = 9 units, thus
\theta=180-\tan^{-1}\left(\frac{4}{5-x}\right)-\tan^{-1}\left(\frac{9}{x}\right)

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.
\frac{d\theta}{dx} = -\frac{4}{x^2-10x+41} + \frac{9}{x^2+81} =0 \\  \\ -4(x^2+81)+9(x^2-10x+41)=0 \\  \\ -4x^2-324+9x^2-90x+369=0 \\  \\ 5x^2-90x+45=0 \\  \\ x^2-18x+9=0 \\  \\ x=9\pm6 \sqrt{2}

Given that x is a point on line segment AB, this means that x is a positive number less than 5.

Thus
x=9-6 \sqrt{2}=0.5147

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
6 0
3 years ago
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