In this case the temperature depends on the hour. So temperature is your X and hour is your Y variable. When h=0, x=0. So the 21*C is you x=0 or y-int point.

If we are trying to match the equation for a line of y=mx+b, 21*C=b.

Our rate of change is -4*C/h, which is our m variable.

So y=(-4)x+(21)

OR in this case, t=-4h+21.

Answer D.

6 0

3 years ago

Read 2 more answers

Help please...... ...

Ket [755]

7&8 if u draw it out first it'll help by tons

5 0

3 years ago

How do I solve this

solniwko [45]

There is your answer

3 0

4 years ago

What is 125^2/3 in simplest form? and What is \sqrt[5]({-245} ) ^{5} in simplest form?

Natasha_Volkova [10]

${ 125 }^{ \frac { 2 }{ 3 } }\\ \\ ={ \left( { 125 }^{ \frac { 1 }{ 3 } } \right) }^{ 2 }\\ \\ ={ \left( \sqrt [ 3 ]{ 125 } \right) }^{ 2 }\\ \\ ={ 5 }^{ 2 }\\ \\ =25$

This is because:

${ a }^{ \frac { m }{ n } }\\ \\ =\sqrt [ n ]{ { a }^{ m } }$

Remember that:

5 x 5 x 5 = 125

5 0

3 years ago