2x^2-7=4
subtract 4 from both sdies
2x^2-11=0
therefor
2x^2=11
divide by 2
x^2=5.5
square root both sdies
x=-2.345 or 2.345
Answer:
x =10
Step-by-step explanation:
Using the pythagoras theorem om one of the right triangle;
(√74)² = (x/2)²+7²
74 = (x/2)²+49
(x/2)² = 74 - 49
(x/2)² = 25
Square root both sides
√ (x/2)² = ±√25
x/2 = ±5
x = 2 * ±5
x = ±10
Hence the value of x is 10
The answer to this question is 30.
Answer:
c
Step-by-step explanation:
