The interval where the function is nonlinear and decreasing is 0 < x < 4
<h3>How to determine the interval where the function is nonlinear and decreasing?</h3>
The straight lines on the graph are the intervals where the graph is linear
This means that the straight lines on the graph will not be considered
Considering the curve, the graph decrease from x = 0 to x = 4
This can be rewritten as:
0 < x < 4
Hence, the interval where the function is nonlinear and decreasing is 0 < x < 4
Read more about function intervals at:
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5 9/16 - 4 1/2= 1 1/16
I got this because you have make the fractions denomenators equal to subtract them. Once you find how to make them equal you need to mutiply the top numbers the same as the bottom so you can make the new fractions that are equal to the ones before. Then you subtract them and the wholes as well. LOOK BELOW.....
9 x1 9
_ = _
16 x1 16
1 x8 8
_ = _
2 x8 16
9/16-8/16= 1/16 of extra miles
5-4=1 of extra miles
1 and 1/16 of extra miles on monday
Answer:
C and C
Step-by-step explanation:
1) (5P + 9)/10 (C)
2) 2 times N plus 1 (C)
1. (-35fi) + 12 + 3i
2. i - 1 + 6i (squared) over i
5. is 0 i think
hope this helped a little bit
