The answer is 24.5. Just plug the numbers in
Answer:
EG = 16 and FH =22
Step-by-step explanation:
We know that the diagonals of a parallelogram bisect each other
so 2a = 3b+2
and 2a+3 = 6b-1
We know have a system of equations to solve
2a = 3b+2
2a+3 = 6b-1
Subtract 3 from each side
2a+3-3 = 6b-1-3
2a = 6b -4
Now we can set the 2 equations equal ( 2a = 3b+2 and 2a = 6b -4)
3b+2 = 6b-4
Subtract 3b from each side
3b-3b+2 = 6b-3b-4
2 = 3b-4
Add 4 to each side
2+4 = 3b-4+4
6 = 3b
Divide by 3
6/3 = 3b/3
2 =b
We want to find a
2a = 3b+2
Substitute in b=2
2a = 3(2) + 2
2a = 6+2
2a =8
Divide by 2
2a/2 =8/2
a = 4
Now that we know a and b
EG = 2a + 3b+2
= 2(4) + 3(2)+2
= 8+6+2
= 16
FH = 2a+3 + 6b-1
= 2(4) +3 +6(2)-1
= 8+3+12-1
= 23-1
= 22
1) 70
2) 110
3) 70
because 110 is equivalent to angle 2. angle 1 and 3 are also equivalent so you add 110 + 110 which equals 220 and subtract 360-220 which equals 140 and divide by 2 to get angles 1 and 3.
(a ± b)² = a² ± 2ab + b² . . . . . . . (signs match)
The middle term is twice the product of the roots of the other two terms. This tells you the terms of the binomial are the square roots of the end terms.
The sign in the binomial will match the sign of the "2ab" term. The order of terms in the binomial doesn't matter. (a±b)² = (b±a)² when signs match.
2^5/2^2 = 2^(5-2)
= 2^3
= 8
