Your second equation has 2 x-intercepts because its curve goes beneath the x-axis, meaning it crosses the x-axis twice. Your first equation has only one x intercept because its vertex touches the x-axis. The transformation that occurred was a vertical shift downwards, (since the image function has that little -7 at the end : ) )
Answer:
The points represent that <u>5 miles </u> were hiked in <u>3 hours.</u>
Step-by-step explanation:
So, lets go over what we need to know.
The x coordinates is the time.
The y coordinates is the miles.
We have (3, 5)
This is (x, y)
x = 3, and y = 5. Considering what we know above, the time is 3 hours, and the miles is 5.
To fill in the boxes, it asks "Blank miles are hiked in blank hours"
We know 5 miles are hiked in 3 hours.
So the fill in for the first part is 5, and the fill in for the second part is 3.
Hope this helps!
Divide the amount from the months , then add the percentage
As a engineer who was mechanical then electrical most buildings, schematics,etc require some form of calculation for some shapes seeing that those shapes are what make up the world. Say for example you need to make something like a mother board pro house knowing it's shape and angle helps make a more accurate structure during the blue printing and build phase. No one just goes in and wings it you need to determine angles for things you don't know that the point of it.
Answer:
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
Step-by-step explanation:
for
I= ∫x^n . e^ax dx
then using integration by parts we can define u and dv such that
I= ∫(x^n) . (e^ax dx) = ∫u . dv
where
u= x^n → du = n*x^(n-1) dx
dv= e^ax dx→ v = ∫e^ax dx = (e^ax) /a ( for a≠0 .when a=0 , v=∫1 dx= x)
then we know that
I= ∫u . dv = u*v - ∫v . du + C
( since d(u*v) = u*dv + v*du → u*dv = d(u*v) - v*du → ∫u*dv = ∫(d(u*v) - v*du) =
(u*v) - ∫v*du + C )
therefore
I= ∫u . dv = u*v - ∫v . du + C = (x^n)*(e^ax) /a - ∫ (e^ax) /a * n*x^(n-1) dx +C = = (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
