3 years ago

What is the y value for the line that passes through (−2,3) and (0,8)

Mathematics

1 answer:

sp2606 [1]3 years ago

3 0

Answer:

y=5x/2 + 9

Step-by-step explanation:

Check the above picture for workings

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Solve log8(x+2)-log8(x-1)=2/3

Alex17521 [72]

You would simplify it too 2.70927 = 2/3

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3 years ago

iren2701 [21]

Are these the actual figures?

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2 years ago

If the parent function f(x)=\root(3)(x) is transformed to g(x)=\root(3)(x+2-4), which is the graph of g(x)?

Arisa [49]

ANSWER

EXPLANATION

The parent function is

$f(x) = \sqrt[3]{x}$

This function is transformed to obtain

$g(x) = \sqrt[3]{x + 2} - 4$

The +2 is a horizontal translation, that shifts the graph of the parent function to the left by 2 units.

The -4 is a vertical translation, that shifts the graph of the parent function down by 4 units.

The correct option is A.

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3 years ago

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What is the first step needed to solve (3/4)x-3=-18 ?

inn [45]

First step is Add 3 to both sides
hope it helps

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2 years ago

Find the square. (1/4A + 1/4B)^2<br><br> a) 1/16A^2 + 1/8AB + 1/16B^2<br> b) 1/4A^2 + 1/8AB + 1/4B^2

alisha [4.7K]

$(a + b)^2 = a^2 + 2ab + b^2$

$(\dfrac{1}{4}A + \dfrac{1}{4}B)^2 =$

$= \dfrac{1}{16}A^2 + \dfrac{1}{8}AB + \dfrac{1}{16}B^2$

Answer: A.

Another way to solve by factoring 1/4.

$(\dfrac{1}{4}A + \dfrac{1}{4}B)^2 =$

$= [\dfrac{1}{4}(A + B)]^2$

$= (\dfrac{1}{4})^2(A + B)^2$

$= \dfrac{1}{16}(A^2 + 2AB + B^2)$

$= \dfrac{1}{16}A^2 + \dfrac{1}{16}2AB + \dfrac{1}{16}B)^2$

$= \dfrac{1}{16}A^2 + \dfrac{1}{8}AB + \dfrac{1}{16}B)^2$

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3 years ago

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