Question

Can you please help me out?

Answer 1

Answer:

- 3.5229

Step-by-step explanation:

Using the rules of logarithms

logx + logy = log(xy)

$log_{10}$ $10^{n}$ = n

Given

$log_{10}$ 3 ≈ 0.4771, then

$log_{10}$ 0.0003

= $log_{10}$ (3 × $10^{-4}$ )

= $log_{10}$ 3 + $log_{10}$ $10^{-4}$

≈ 0.4771 - 4

≈ - 3.5229 ( to 4 dec. places )