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2 years ago

Can anyone help me with this click to see

Mathematics

2 answers:

Natalka [10]2 years ago

4 0

Answer:

-3,-5,-6,-10

Step-by-step explanation:

nalin [4]2 years ago

4 0

Answer:

-3 -5 -6 -10

Step-by-step explanation:

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Hakeem subtracted 8 from a number, then multiplied the difference

Inessa [10]

Answer:

Step-by-step explanation:

(×-8)5=20

(5×-40)=20

5×(-40+40)=(20+40)

5×=60

5×÷5=60÷5

×=12

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2 years ago

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What is the force acting on a 16 kg object accelerating at 2.0 m/s2

alexira [117]

Answer:

32 n

Step-by-step explanation:

I had the same problem but I used a net force calculator the formula is F=MA so it would be 32=16/2.0 :)

6 0

2 years ago

Determine algebraically all points where the graphs of XY equal 10 and Y equals X +3 intersect

Gelneren [198K]

XY=10
Y=X+3
X(X+3)=10
X^2+3X=10
X^2+3X-10
(X-2)(X+5)

6 0

3 years ago

HI! I HAVE A TEST ON MONDAY AND IM TRYING TO STUDY, IM KINDA STUCK ON HOW TO DO THIS PROBLEM..

sergij07 [2.7K]

Answer: See below

Step-by-step explanation:

number of yellow pieces/number of blue pieces

= 14/24

= 7/12 --> 7 to 12 --> 7:12

The ratio that represents the number of yellow pieces to the total number of pieces is part-to-whole

number of yellow pieces/total number of pieces

= 14/100

= 7/50 --> 7 to 50 --> 7:50

The ratio that represents the number of blue pieces to the total number of pieces is part-to-whole

= 24/100

= 6/25 --> 6 to 25 --> 6:25

8 0

1 year ago

1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n

Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

70% of fatalities involve an intoxicated driver, hence $p = 0.7$ .

A sample of 15 fatalities is taken, hence $n = 15$ .

The probability is:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

Hence

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061$

$P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186$

$P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700$

$P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916$

$P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305$

$P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047$

Then:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215$

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0

2 years ago