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belka [17]
3 years ago
6

Two numbers are randomly selected from integers 1 through 9. What is the probability that only one of the integers is odd given

that the sum of the two numbers is odd?
Mathematics
1 answer:
12345 [234]3 years ago
6 0

Answer: i think its just 1

Step-by-step explanation:

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What’s the value and what makes the x in the equation -6(x+11)+ 2x = 70 true ?
madreJ [45]

Answer:

x=-34

Step-by-step explanation:

isolate the variable by diving each side by the factors that don't contain a variable.

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4 years ago
If p q r is prime numbers such that pq+r=73, what is the least possible value of p+q+r
Jobisdone [24]
The answer to this question would be: p+q+r = 2 + 17 + 39= 58

In this question, p q r is a prime number. Most of the prime number is an odd number. If p q r all odd number, it wouldn't be possible to get 73 since
odd x odd + odd= odd + odd = even
Since 73 is an odd number, it is clear that one of the p q r needs to be an even number. 

There is only one odd prime number which is 2. If you put 2 in the r the result would be:
pq+2= 73
pq= 71
There will be no solution for pq since 71 is prime number. That mean 2 must be either p or q. Let say that 2 is p, then the equation would be: 2q + r= 73

The least possible value of p+q+r would be achieved by founding the highest q since its coefficient is 2 times r. Maximum q would be 73/2= 36.5 so you can try backward from that. Since q= 31, q=29, q=23 and q=19 wouldn't result in a prime number r, the least result would be q=17
r= 73-2q
r= 73- 2(17)
r= 73-34=39

p+q+r = 2 + 17 + 39= 58
6 0
3 years ago
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Can i have help on this pls can you classify 17.3 in as many groups as possible
PIT_PIT [208]

It can go into the group integers, as well as rational numbers.

Hope this helps you! Happy thanksgiving, here's a turkey!

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3 years ago
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