You can take the log of the left and right hand side, and then apply the <span>logarithm rules:
log(a</span>ˣ) = x·log(a)
log(ab) = log(a) + log(b)
log(9^(x-1) * 2^(2x+2)) = log(6^(3x))
log(9^(x-1)) + log(2^(2x+2)) = 3x log(6)
(x-1) log(9) + (2x+2) log(2) - 3x log(6) = 0
x(log9 + 2log2 - 3log6) = log9 - 2log2
x = (log9 - 2log2) / (log9 + 2log2 - 3log6)
simplifying by writing log9 = 2log3 and log6 = log2+log3
x= 2(log3 - log2) / (2log3 + 2log2 - 3log2 - 3log3) =
x= -2(log3 - log2) / (log3 + log2) = -2 log(3/2) / log(6)
So 6^x = 4/9
Answer:
Undefined
<em>Step </em><em>by</em><em> step</em><em> </em><em>explaination:</em>
<em> </em>
by order of operations we know that we multiply first;
so, 0x-(7*9)=0
1) Multiply the ones in brackets first:
0x-63=0
2) To make X the subject perform the opposite operation:
0x-64+63=0+63
0x=63
3) Divide 0 on both sides;
0x/0= 63/0
therefore; <u>x is undefined</u>
65754.6 because the 9 in the hundreds place bumps up the five in the tenths
So, let's say that all the dogs had a number of x.
then 1/12 x were the Hound Group dogs.
then, out of the Hound Group,, that is 1/12 x, 3/10 were English Foxhounds.
For this, we need to multiply the fractions:
so of all the dogs at the show, the English Foxhunds were a 1/40 fraction,
Answer:
x=7
Step-by-step explanation:
