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expeople1 [14]
3 years ago
11

Look at the sample space below. {1, 2, 3, 7, 9, 10, 15, 19, 20, 21} When chosen randomly, what is the probability of picking an

odd number? P(odd number) = Question 5 options: 1/21 3/10 7/10 1/2 ANSWER AND GET 20 POINTS
Mathematics
2 answers:
maw [93]3 years ago
8 0

Answer:

the probability of picking an odd number is 7/10

crimeas [40]3 years ago
8 0

Answer:

The probability of getting an odd number is 7/10.

Step-by-step explanation:

There are 7 odd numbers: {1, 3, 7, 9, 15, 19, 21}

There are 3 even numbers: {2, 10, 20}

There are 10 numbers overall: {1, 2, 3, 7, 9, 10, 15, 19, 20, 21}

7 odd numbers out of 10 numbers is equal to 7/10

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I have been trying to figure this out no luck.​
algol [13]

Answer:

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Round 112.3398 to the nearest hundredth. Enter your answer in the space<br> provided.
ICE Princess25 [194]

Answer:

112.34

Step-by-step explanation:

The 2nd digit after the decimal point is in the hundredths position.

• If the digit following is ≥ 5 then round up

• If the digit following is < 5 then leave digit as it is

here the digit following the 3 in the hundredths position is 9 so round up

112.3398 ≈ 112.34 ( to the nearest hundredth )

5 0
2 years ago
Hi i need to solve this problem but i forgot. I do know though that you have too use the distributive property. a+ny=n?
Thepotemich [5.8K]
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5 0
3 years ago
Triangle MNO is reflected over the x-axis and then translated up 4 and right 3. On a coordinate plane, triangle O M N has points
Schach [20]

Answer:

Option A. Translate the pre-image down 4 and right 3 and then reflect the figure over the x-axis

Step-by-step explanation:

8 0
3 years ago
The shuttle bus from your parking lot and your office building operates on a 15 minute schedule. You arrive at the parking lot a
mylen [45]

Answer:

(a) The standard deviation of your waiting time is 4.33 minutes.

(b) The probability that you will have to wait more than 2 standard deviations is 0.4227.

Step-by-step explanation:

Let <em>X</em> = the waiting time for the bus at the parking lot.

The random variable <em>X</em> is uniformly distributed with parameters <em>a</em> = 0 to <em>b</em> = 15.

The probability density function of <em>X</em> is given as follows:

f_{X}(x)=\frac{1}{b-a};\ a

(a)

The standard deviation of a Uniformly distributed random variable is given by:

SD=\sqrt{\frac{(b-a)^{2}}{12}}

Compute the standard deviation of the random variable <em>X</em> as follows:

SD=\sqrt{\frac{(b-a)^{2}}{12}}

      =\sqrt{\frac{(15-0)^{2}}{12}}

      =\sqrt{\frac{225}{12}}

      =\sqrt{18.75}\\=4.33

Thus, the standard deviation of your waiting time is 4.33 minutes.

(b)

The value representing 2 standard deviations is:

X=2\times SD=2\times4.33=8.66

Compute the value of P (X > 8.66) as follows:

P(X>8.66)=\int\limits^{10}_{8.66} {\frac{1}{15-0}}\, dx\\

                    =\frac{1}{15}\times \int\limits^{10}_{8.66} {1}\, dx\\

                    =\frac{1}{15}\times |x|^{15}_{8.66}\\

                    =\frac{15-8.66}{15}\\

                    =0.4227

Thus, the probability that you will have to wait more than 2 standard deviations is 0.4227.

4 0
3 years ago
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