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algol13
3 years ago
14

The rate of change of y with respect to x is proportional to y2. Write a differential equation for the statement. (Use k for the

constant of proportionality.)
Mathematics
1 answer:
Triss [41]3 years ago
7 0

Answer:

\dfrac{dy}{dx}\  = ky_2

Step-by-step explanation:

The rate of change of y with respect to x is expressed as shown;

\dfrac{dy}{dx}

If the rate of change of y with respect to x is proportional to y2, this is expressed as;

\dfrac{dy}{dx}\  \alpha \ y_2

If we remove the proportionality sign, a proportionality constant will be introduced as shown;

\dfrac{dy}{dx}\  = ky_2

where k is the constant of proportionality.

Hence the differential equation for the statement is expressed as \dfrac{dy}{dx}\  = ky_2

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Caden exercises daily by walking on a treadmill. He sets the machine so that he will walk at a steady rate of 3.6 miles per hour
babunello [35]

Answer:

a) d = 3.6t

b) 10.8 miles

c) 1.2 hours

Step-by-step explanation:

For part a:

Slope of a line: y = mx + b

In this case, the equation would be: d = mt,

where m represents the speed Caden is walking at.

Note: b = 0 in this case because when Caden starts walking on the treadmill, he hasn't really covered any distance yet.

Therefore, plugging in a speed of 3.6 miles per hour, the equation is:

d = 3.6t

For part b:

This is a simple instance of plugging in 3 hours for our t value.

Therefore, d = 3.6 (3)

d = 10.8 miles

For part c:

In this case, we are given that d = 4.32 miles.

Therefore, 4.32 = 3.6t

Dividing both sides by 3.6, we get

t = 1.2 hours

5 0
3 years ago
Hi- I need help please to get my HS diploma...did not graduate :(
andrew-mc [135]

The remainder from the division of the algebraic equation is -53/8.

<h3>What is the remainder of the algebraic expression?</h3>

The remainder of the algebraic expression can be determined by using the long division method.

Given that:
\mathbf{f(x) = \dfrac{x^3 - 6x^2 + 3x - 1}{2x-3}}

where:

  • The divisor = 2x -3

Using the long division method, we have:

\mathbf{= \dfrac{x^2}{2} +\dfrac{-\dfrac{9x^2}{2}+3x -1 }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} +\dfrac{-\dfrac{-15x}{4}-1 }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}+\dfrac{-\dfrac{53}{8} }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}-\dfrac{53 }{8(2x-3)}}

Therefore, we can conclude that the remainder is -53/8.

Learn more about the division of algebraic equations here:

brainly.com/question/4541471

#SPJ1

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2 years ago
NEED HELP IN TEST Please
Elden [556K]

Answer:

did you try

Step-by-step explanation:

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3 years ago
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jek_recluse [69]
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