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USPshnik [31]
3 years ago
6

How do I do these!?!

Mathematics
2 answers:
Tanya [424]3 years ago
6 0

If the measure of angle 4 is 94°, each angle congruent to it will be 94°. Angles 2, 4, 6, and 8 are the same and the angles 1, 3, 5, and 7 are the same. The straight line (I believe it's a transversal) divides the parallel lines and it is slightly tilted, which is why angles 2, 4, 6, and 8 are 94° instead of 90°.

The angle of say, 2 and 3 added, is equal to 180° which makes it supplementary. That means if we know angle 2 is 94°, we can subtract that from 180° to find the angle of 3 and the subsequent odd angles. 180 - 94 = 86 so angles 1, 3, 5, and 7 are 86°.

Hope this helps

abruzzese [7]3 years ago
5 0

Answer:

You use angles and stuff

Step-by-step explanation:

angles

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What is the solution to the equation 4x-6= 10x-3?<br>​
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What are the zeros of the polynomial function: f(x) = x3 – 5x2 -6x
shepuryov [24]

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<u>Solution:</u>

Given, polynomial equation is x^{3}-5 x^{2}-6 x

We have to find the zeroes of the given polynomial.

So, let us equate it with 0.

\begin{array}{l}{\text { Then, } x^{3}-5 x^{2}-6 x=0} \\\\ {\rightarrow x\left(x^{2}-5 x-6\right)=0} \\\\ {\rightarrow x\left(x^{2}-(6-1) x-6\right)=0} \\\\ {\rightarrow x\left(x^{2}-6 x+x-6\right)=0} \\\\ {\rightarrow x(x(x-6)+1(x-6))=0} \\\\ {\rightarrow x(x-6)(x+1)=0} \\\\ {\rightarrow x=0 \text { or } x-6=0 \text { or } x+1=0} \\\\ {\rightarrow x=0 \text { or } 6 \text { or }-1}\end{array}

Hence, the roots of the given polynomial are -1, 0, 6.

6 0
3 years ago
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