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Ilya [14]
3 years ago
13

Caden exercises daily by walking on a treadmill. He sets the machine so that he will walk at a steady rate of 3.6 miles per hour

.
A. If t represents time in hours and d represents distance in miles write an equation that models the relationship between these variables

B. Use your equation to calculate the distance Caden will walk in 3 of an hour .

C. Use your equation to calculate how long it will take for Caden to walk 4.32 miles

(i have to write sumn for this part)​
Mathematics
1 answer:
babunello [35]3 years ago
5 0

Answer:

a) d = 3.6t

b) 10.8 miles

c) 1.2 hours

Step-by-step explanation:

For part a:

Slope of a line: y = mx + b

In this case, the equation would be: d = mt,

where m represents the speed Caden is walking at.

Note: b = 0 in this case because when Caden starts walking on the treadmill, he hasn't really covered any distance yet.

Therefore, plugging in a speed of 3.6 miles per hour, the equation is:

d = 3.6t

For part b:

This is a simple instance of plugging in 3 hours for our t value.

Therefore, d = 3.6 (3)

d = 10.8 miles

For part c:

In this case, we are given that d = 4.32 miles.

Therefore, 4.32 = 3.6t

Dividing both sides by 3.6, we get

t = 1.2 hours

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Therefore, the number -14-5i is in the 3rd quadrant because it graphed to the left of the origin and down.
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Gnesinka [82]
A.
the y intercept is where x=0
x represents the number of months
when the number of months is 0, that is the initial number of games won

that looks to be a little below y=2, so maybe y=1.8?
the y intercept is y≈1.8
it represents the number of games won with 0 months of practice



B.
we can use y=mx+b
m=slope
b=y intercept
we know the y intercept
find the slope
slope=rise/run
the I'm going from x=0 to x=10
the rise is about 18.95 (from 1.8 to 20.75)
the run is 10
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the equation would be y=1.895x+1.8
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6 0
3 years ago
Choose the correct converse.
a_sh-v [17]

Answer:

i think it is B i am not sure

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Help me with these math questions.
Olegator [25]

graph A

no x-intercept

no y-intercept

H.A is y = 5

V. A. is x = 0

*****************************************

Answer: \frac{150}{31}

<u>Step by step explanation:</u>

log₆(5x + 6) - log₆(x - 4) = 2

log₆(\frac{5x+6}{x-4}) = 2

(\frac{5x+6}{x-4}) = 6²

(\frac{5x+6}{x-4}) = 36

5x + 6 = 36(x - 4)

5x + 6 = 36x - 144

       6 = 31x - 144

    150 = 31x

     \frac{150}{31} = x

**********************************************************

Answers:

  • a. (-1, -5)
  • b. up
  • c. x = -1
  • d. \frac{-2+\sqrt{15}}{3} and\frac{-2-\sqrt{15}}{3}
  • e. -2
  • f. see attachment
  • g. domain (-∞, ∞)  range [-5, ∞)

<u>Explanation:</u>

f(x) = 3x² + 6x - 2

      a=3  b=6 c=-2

x = \frac{-b}{2a} =\frac{-6}{2(3)} = \frac{-6}{6} = -1

Axis Of Symmetry: x = -1

f(-1) = 3(-1)² + 6(-1) - 2

       = 3 - 6 - 2

       = -5

Vertex: (-1, -5)

x = \frac{-b+/-\sqrt{b^{2}-4ac}}{2a}

  = \frac{-6+/-\sqrt{6^{2}-4(3)(-2)}}{2(3)}

  = \frac{-6+/-\sqrt{36+24}}{6}

  = \frac{-6+/-\sqrt{60}}{6}

  = \frac{-6+/-2\sqrt{15}}{6}

  = \frac{-2+/-\sqrt{15}}{3}

x-intercepts: \frac{-2+/-\sqrt{15}}{3}



6 0
3 years ago
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