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3 years ago

I NEED HELP PLEASE IM BEGGING YOU PLEASE HELP!! IM B EGGING YOU PLEASE!!

Mathematics

1 answer:

Monica [59]3 years ago

3 0

Answer:

are there any answer choices?

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What is the answer? A B C D

Ilya [14]

Answer:

Step-by-step explanation:

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2 years ago

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What is an equation of the line that passes through the point (4, -1) and has

Nuetrik [128]

Answer:

y + 1 = -5(x - 4)

y + 1 = -5x + 20

y = -5x + 19

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3 years ago

8 Vanesa wants to find the volume

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Cubic inches. Think how small a lunchbox is.

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3 years ago

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Six different second-year medical students at Bellevue Hospital measured the blood pressure of the same person. The systolic re

Yanka [14]

Answer:

$Range=14$

$\sigma^2 =32.4$

$\sigma = 5 .7$

The standard deviation will remain unchanged.

Step-by-step explanation:

Given

$Data: 136, 129, 141, 139, 138, 127$

Solving (a): The range

This is calculated as:

$Range = Highest - Least$

Where:

$Highest = 141; Least = 127$

So:

$Range=141-127$

$Range=14$

Solving (b): The variance

First, we calculate the mean

$\bar x = \frac{1}{n} \sum x$

$\bar x = \frac{1}{6} (136+ 129+ 141+ 139+ 138+ 127)$

$\bar x = \frac{1}{6} *810$

$\bar x = 135$

The variance is calculated as:

$\sigma^2 =\frac{1}{n-1}\sum(x - \bar x)^2$

So, we have:

$\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]$

$\sigma^2 =\frac{1}{5}*[162]$

$\sigma^2 =32.4$

Solving (c): The standard deviation

This is calculated as:

$\sigma = \sqrt {\sigma^2 }$

$\sigma = \sqrt {32.4}$

$\sigma = 5 .7$ --- approximately

Solving (d): With the stated condition, the standard deviation will remain unchanged.

5 0

2 years ago