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DedPeter [7]
3 years ago
8

What is the exponent in the power of 10?

Mathematics
1 answer:
Arisa [49]3 years ago
4 0
X^10 the exponent would be 10
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3 years ago
By selling a cow for Rs 144, there is a profit of the same percentage as its cost price. Find the cost price.​
hjlf

Answer:

Step-by-step explanation:

<h2><u>☼︎</u><u>Answer:</u></h2>

The cost price of cow = Rs.80

Explanation:

<h2><u>☼︎</u><u>Given :-</u></h2>

  • By selling a cow for Rs 144, there is a profit of the same percentage as its cost price.
<h2><u>☼︎</u><u>T</u><u>o Find</u><u>:</u><u>-</u></h2>

  • The cost price.
<h2 /><h2 /><h2><u>☼︎</u><u>L</u><u>e</u><u>t</u><u>:</u><u>-</u></h2>

  • The cost price of cow = Rs.x

<h2><u>☼︎</u><u>Solution :-</u></h2>

\sf x + x \: of \: x\%= 144 \\ \\ \sf \implies x + \frac{x \times x}{100} = 144 \\ \\ \sf \implies {x}^{2} + 100x - 14400 = 0 \\ \\ \sf \implies x(x - 80) + 180(x - 80) = 0 \\ \\ \sf \implies x + 180 = 0 \\ \\ \sf \implies x = - 180 \\ \\ \sf \therefore \:  {\boxed{ \sf \pink{x = 80}}}

<h2><u>Hence: </u></h2>

The cost price of cow =<u>R</u><u>s</u><u>8</u><u>0</u>

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3 years ago
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Given f(x) = 17-x^2, what is the average rate of change in f(x) over the interval [1, 5]
pentagon [3]
Average rate of change  over [1,5]   = f(5) - f(1)  /  5 - 1

=  [(17-5^2) - (17-1) ] / 4

=  (-8 - 16)  /  4  = -24 / 4  = -6 Answer
3 0
3 years ago
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