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Radda [10]
3 years ago
10

How to multiply 2^4 tell fast im waiting

Mathematics
2 answers:
dolphi86 [110]3 years ago
6 0

Answer:

2+2+2+2 is equal to 2*4

Step-by-step explanation:

2*4= 8

liraira [26]3 years ago
4 0

Answer:

Command

Simplify

2 power of 4

16

2 power of 4

Step-by-step explanation:

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Brrunno [24]

f(x)=x²-1  
g(x)=2x-3
f(x)*g(x)=(x²-1)*(2x-3)-----------> <span>this function exists for all real numbers</span>

the answer is the interval (-∞,∞)

using a graph tool see the attached figure

6 0
4 years ago
4/7m = 2/7( 2m+1 )<br> What is M?<br> Check Solution
aev [14]
4/7m = 2/7(2m + 1)
4/7m = 4/7m + 2/7
4/7m - 4/7m = 2/7
0 = 2/7 (incorrect)

no solution
5 0
3 years ago
Read 2 more answers
How to solve 2×4÷3+5
Nataly [62]

You will need to follow order of operations, which states that operations must be completed in the following order: parentheses, exponents, multiplication and division, and then addition and subtraction.


In this case, there are no parentheses and no exponents, so we will start with the multiplication and division:

2 \cdot 4 \div 3 + 5 = (2 \cdot 4 \div 3) + 5

\Bigg(\dfrac{8}{3} \Bigg) + 5


Now, we will finish by doing addition and subtraction:

\Bigg(\dfrac{8}{3} \Bigg) + 5 = \dfrac{8}{3} + \dfrac{15}{3}

\dfrac{8 + 15}{3}

\boxed{\dfrac{23}{3}}


Our answer is \boxed{\dfrac{23}{3}}.

3 0
3 years ago
Read 2 more answers
PLEAASEE HELP ANYONE
BabaBlast [244]
Not a 100% positive but I believe that your answer would be C.
8 0
3 years ago
Read 2 more answers
In an investigation of pregnancy-induced hypertension, one group of women with this disorder was treated with low-dose aspirin,
AleksandrR [38]

Answer:

Step-by-step explanation:

Given that in an investigation of pregnancy-induced hypertension, one group of women with this disorder was treated with low-dose aspirin, and a second group was given a placebo. A sample consisting of 50 women who received aspirin has mean arterial blood pressure 120mmHg and standard deviation 10mmHg; a sample of 42 women who were given the placebo has mean blood pressure 115mmHg and standard deviation 12mmHg.

Population variances are equal

H_0: \bar x = \bar y\\H_a: \bar x \neq \bar y

(two tailed test at 5% significance level)

Here x denotes group I and Y group II

                  N       Mean     StDev SE Mean

Sample 1   50     120      10  1.4142

Sample 2 42       115      12  1.8516

Pooled std deviation = 10.9565

df=80

Mean difference= 5

Test statistic t = mean diff/std error = \frac{5}{2.3299}=2.1803

p value = 0.0318

since p <0.05 we reject H0

b) We find p >0.01 hence at 1% significance level we accept H0

This implies that 99% confidence interval contains mean difference =0

4 0
4 years ago
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