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3 years ago

Pls help i dont really understand this type of thing

Mathematics

1 answer:

pochemuha3 years ago

4 0

Shiii me neither maybe ask your teacher

You might be interested in

-2(x+1)+5x= 3(x+1) - 2

cricket20 [7]

Answer:

no solution

Step-by-step explanation:

-2x - 2 + 5x = 3x + 3 - 2

3x - 2 = 3x + 1

3x = 3x + 3

0 = 3

no solution

6 0

3 years ago

Round to the nearest hundredth if necessary. <br> 2 qt =______ mL<br> help me pleaseeeee

Rasek [7]

It would be 1892.71

6 0

3 years ago

Find the slope of the line 5x-2y=10A. 2/5B. -5C. -2/5D. 5/2

sammy [17]

5x - 2y = 10

Isolating y:

-2y = 10 - 5x

y = (10 - 5x)/(-2)

y = 10/(-2) + (-5x)/(-2)

y = -5 + 5/2x

This equation has the slope-intercept form with a slope of 5/2 and a y-intercept of -5

5 0

1 year ago

Need help asap rocky :))

antoniya [11.8K]

The value of ∠EOF is 75°.

Step-by-step explanation:

Let us take O be the center of the circle.

Given,

∠AOB = 45°

∠COD = 60°

To find the ∠EOF (value of x)

Now,

Since AD is the diameter of the circle, ∠AOD = 180°

∠AOB+∠COD+∠BOC = ∠AOD

Or, 45°+60°+∠BOC = 180°

or, ∠BOC = 180°-(45°+60°)

= 75°

Again,

∠BOC = ∠EOF as they are vertically opposite angle.

Hence,

∠EOF = 75°

4 0

3 years ago

Read 2 more answers

PLEASE HELP a three dight number has one more ten than it has hundreds, and it also has one more than twice as many units as ten

bija089 [108]

The reverse number of the three-digit number is 732

<h3>How to determine the reverse of the number?</h3>

Let the three-digit number be xyz.

So, the reverse is zyx

This means that

Number = 100x + 10y + z

Reverse = 100z + 10y + x

From the question, we have the following parameters:

y = x + 1

z = 1 + 2y

The sum is represented as:

100x + 10y + z + 100z + 10y + x = 10^3 - 31

100x + 10y + z + 100z + 10y + x = 969

Evaluate the like terms

101x + 101z + 20y = 969

Substitute y = x + 1

101x + 101z + 20(x + 1) = 969

101x + 101z + 20x + 20 = 969

Evaluate the like terms

101x + 101z + 20x = 949

121x + 101z = 949

Substitute y = x + 1 in z = 1 + 2y

z = 1 + 2(x + 1)

This gives

z = 2x + 3

So, we have:

121x + 101z = 949

121x + 101* (2x + 3) = 949

This gives

121x + 202x + 303 = 949

Evaluate the sum

323x = 646

Divide by 323

x = 2

Substitute x = 2 in z = 2x + 3 and y = x + 1

z = 2*2 + 3 = 7

y = 2 + 1 = 3

So, we have

x = 2

y = 3

z = 7

Recall that

Reverse = 100z + 10y + x

This gives

Reverse = 100*7 + 10*3 + 2

Evaluate

Reverse = 732

Hence, the reverse number of the three-digit number is 732