Answer:

Explanation:
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Based on the given chemical reaction, as 31.2 mL of hydrogen are yielded, one computes its moles via the ideal gas equation under the stated conditions as shown below:

Now, since the relationship between hydrogen and magnesium is 1 to 1, one computes its milligrams by following the shown below proportional factor development:

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Answer:
High density, metallic bonds
Explanation:
We may look at this question from the structural properties of the metals:
- metals in their solid states are the most dense phases of all the standard phases we know (solids, liquids and gases). This means the particles within a metal lattice are very closely packed. Both heat and electricity is conducted when particles interact and touch one another, so that either energy or electric current might travel from one particle to the other easily. High density means low distances between the atoms, so they can interact easily;
- the main reason, however, is the fact that metals form metallic bonds, also known as 'sea of electrons'. We have metal cations floating in a sea of their valence electrons. This forms a medium in which both heat and electricity can travel easily.
Answer:
Explanation:3.2 ft 2 fti2 ft 4 ft ft2
Answer:
D
Explanation:
When a dilution is made, a volume of the stock solution is collected and then is mixed to the solvent. The total amount of the solute (number of moles or mass), must be equal in the volume of the sample and at the final volume, because of the Lavoiser's law (the matter can't be created nor destructed).
The mass or the number of moles is the concentration (C) multiplied by the volume (V), so, if 1 is the sample of the stock solution, and 2 the diluted solution:
C1*V1 = C2*V2
The final volume of the solution is 10 mL. So, let's identify the volume needed for each stock solution.
Acetaminophen
C1 = 500 ug/L
C2 = 50 ug/L
500*V1 = 50*10
V1 = 1 mL
Dextromethorphan
C1 = 1 mM = 1000 uM
C2 = 20 uM
1000*V1 = 20*10
V1 = 0.2 mL
So, the volume of water needed is the total less the volume of the stocks solutions less the volume of the embryo water:
V = 10 - 1 - 1 - 0.2 = 7.8 mL
Thus, to to the solution, it's necessary to add at 1 mL of the embryo water 1 ml of 500 ug/I acetaminophen and 0.2 ml of 1 mM dextromethorphan, and 7.8 ml of water.