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MA_775_DIABLO [31]
2 years ago
12

List three ways in witch the water reaches the atmosphere

Chemistry
1 answer:
meriva2 years ago
7 0
Three ways water reaches from earth to atmosphere are
1. direct evaporation from the water bodies like sea,river,oceans
2. moisture from the land(you must have seen land dries out)
3.moisture from the plant(small capillaries from the plants sucks water from land n goes to atmosphere in form of vapour from leaves)
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Are changes in the state of matter (phase) considered physical or chemical changes? Why?
Flauer [41]

Answer:

Physical changes

Explanation:

Changes in the state of matter are physical changes.

First, the material is made up of the same components that is was before it changed states.

The physical properties of the material changed, but its chemical composition did not, meaning that is is a physical change.

3 0
3 years ago
Please help with this question
tamaranim1 [39]
1.806x10^24
Written equation form(always start the equation off with what you know based off of the question!):

3mol(CCl4)•6.022x10^23/1mol = 1.806x10^24

Good luck!
3 0
3 years ago
The layering of eroded sediments is called:
Aleks [24]
4. the rock cycle is the layering of eroded sediments 
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3 years ago
Which event is caused by gravity?​
Oxana [17]

Answer:

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Explanation:

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6 0
3 years ago
Show
SIZIF [17.4K]

Answer: 0.9375 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}     .....(1)

Molarity of HCl solution = 0.75 M

Volume of HCl solution = 25.0 mL = 0.025 L

Putting values in equation 1, we get:

\text{Moles of} HCl={0.75}\times{0.025}=0.01875moles  

CaCO_3(s)+2HCl(aq)\rightarrow CaCl_2(s)+CO_2(g)+H_2O(l)  

According to stoichiometry :

2 moles of HCl require = 1 mole of CaCO_3

Thus 0.01875 moles of HCl will require=\frac{1}{2}\times 0.01875=0.009375moles  of CaCO_3

Mass of CaCO_3=moles\times {\text {Molar mass}}=0.009375moles\times 100g/mol=0.9375g

Thus 0.9375 g of CaCO_3 is required to react with 25.0 ml of 0.75 M HCl

6 0
2 years ago
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