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3 years ago

If a guy named josh got 45 bucks for his b-day and already had 237 bucks. How much money does josh have all together.

Mathematics

2 answers:

Lisa [10]3 years ago

8 0

Answer:

That’s easy it is 282

Step-by-step explanation:

saul85 [17]3 years ago

3 0

He will now have 282 bucks altogether.

Step-by-step explanation:

We already know that he has 237 bucks before his birthday, but now he has an additional 45 bucks that he got from his birthday. With this, you can create an equation that looks like this: 237+45. You then solve the equation by adding 45 to 237, which gets you 282 bucks altogether.

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Step-by-step explanation:

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3 years ago

Simplify the expression 3/2 (5/3) -1 1/4 + 1/2 Given the answer as a simplified fraction. The simplified expression is a/b.

ella [17]

<h2>Hello!</h2>

The answer is:

The simplified fraction is:

$\frac{7}{4}$

To solve this problem we must remember the following:

- Addition or subtraction of fractions, we add or subtract fractions by the following way:

$\frac{a}{b}(+-)\frac{c}{d}=\frac{ad(+-)bc}{bd}$

- Product of fractions, the multiplication of fraction is linear, meaning that we should multiply the numerator by the numerator and denominator by denominator, so:

$\frac{a}{b}*\frac{c}{d}=\frac{ac}{bd}$

- Convert mixed number to fraction,

$a\frac{b}{c}=a+\frac{b}{c}=\frac{ac+b}{c}$

So, solving we have:

$\frac{3}{2}*\frac{5}{3}-1\frac{1}{4}+\frac{1}{2}=\frac{3*5}{2*3} -1\frac{1}{4}+\frac{1}{2}\\\\\frac{3*5}{2*3} -1\frac{1}{4}+\frac{1}{2}=\frac{15}{6} -1\frac{1}{4}+\frac{1}{2}\\\\\frac{15}{6} -1\frac{1}{4}+\frac{1}{2}=\frac{15}{6} -(1+\frac{1}{4})+\frac{1}{2}\\\\\frac{15}{6} -(1+\frac{1}{4})+\frac{1}{2}=\frac{15}{6}-(\frac{4+1}{1*4})+\frac{1}{2}\\\\\frac{15}{6}-(\frac{4+1}{4})+\frac{1}{2}=\frac{15}{6}-\frac{5}{4}+\frac{1}{2}$

$\frac{15}{6}-\frac{5}{4}+\frac{1}{2}=(\frac{5}{2}-\frac{5}{4})+\frac{1}{2}\\\\(\frac{5}{2}-\frac{5}{4})+\frac{1}{2}=(\frac{(4*5)-(2*5)}{8})+\frac{1}{2}\\\\(\frac{(4*5)-(2*5)}{8})+\frac{1}{2}=(\frac{20-10}{8})+\frac{1}{2}\\\\(\frac{20-10}{8})+\frac{1}{2}=(\frac{10}{8})+\frac{1}{2}\\\\(\frac{10}{8})+\frac{1}{2}=\frac{5}{4}+\frac{1}{2}\\\\\frac{5}{4}+\frac{1}{2}=\frac{(5*2)+(4*1)}{2*4}\\\\\frac{(5*2)+(4*1)}{2*4}=\frac{10+4}{8}=\frac{14}{8}\\\\\frac{14}{8}=\frac{7}{4}$