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Ann [662]
3 years ago
7

Solve the equation -3(x-14)+9x=6x+42. Does the equation have one solution, no solution, or infinitely many solutions?

Mathematics
2 answers:
Serggg [28]3 years ago
7 0

Answer:

-3x+42+9x=6x+42

0x=0

x=0

Step-by-step explanation:

there is no solution

makvit [3.9K]3 years ago
7 0

Answer:

infinitely many solutions

Step-by-step explanation:

Given

- 3(x - 14) + 9x = 6x + 42 ← distribute and simplify left side

- 3x + 42 + 9x = 6x + 42

6x + 42 = 6x + 42

Since the equation is the same on both sides, then any real value of x is a solution.

That is has infinite solutions

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miss Akunina [59]
Equilateral triangles
7 0
4 years ago
Read 2 more answers
The manager of a new supermarket wished to estimate the likely expenditure of his customers. A sample of till slips from a simil
bagirrra123 [75]

Answer:

0.0228 = 2.28% probability that any shopper selected at random spends more than $80 per week.

88.54% of shoppers are expected to spend between $30 and 80 per week.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of $50 and a standard deviation of $15.

This means that \mu = 50, \sigma = 15

Find the probability that any shopper selected at random spends more than $80 per week?

This is 1 subtracted by the p-value of Z when X = 80. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{80 - 50}{15}

Z = 2

Z = 2 has a p-value of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that any shopper selected at random spends more than $80 per week.

Find the percentage of shoppers who are expected to spend between $30 and 80 per week?

The proportion is the p-value of Z when X = 80 subtracted by the p-value of Z when X = 30.

X = 80

Z = \frac{X - \mu}{\sigma}

Z = \frac{80 - 50}{15}

Z = 2

Z = 2 has a p-value of 0.9772

X = 30

Z = \frac{X - \mu}{\sigma}

Z = \frac{30 - 50}{15}

Z = -1.33

Z = -1.33 has a p-value of 0.0918

0.9772 - 0.0918 = 0.8854

0.8854*100% = 88.54%

88.54% of shoppers are expected to spend between $30 and 80 per week.

8 0
3 years ago
How do you factor this in the form (x+b)(x+c)
faust18 [17]
So you have your polynomial. To factor this out, you need to find the factors of -45 that will add up to 3. These two factors would be -5 and 8. So, you have factored your polynomial! (x-5)(x+8). If you are still unsure, simply use the FOIL method to check and see if you get the same polynomial back. Hope this helps!
7 0
4 years ago
Halp me :<<<<<<<<<<<<<<​
lisabon 2012 [21]

Answer:

4^2+2^2, 5^2, 6^2-6

Step-by-step explanation:

4 to the power of 2 is 16 and 2 to the power of 2 is 4. 16+4 is 20.

5 to the power of 2 is 25 which is greater than 20.

6 to the power of 2 is 36 minus 6 is 30 which is greater than 25 and 20.

7 0
3 years ago
1. Given that 4x²- 16x + 15 = a(x-p)²+ q for all values of x.
FinnZ [79.3K]

Answer:

a = 4, p = 2, q = - 1

Step-by-step explanation:

Expand the right side of the identity, then compare the coefficients of like terms with those on the left side.

a(x - p)² + q ← expand (x - p)² using FOIL

= a(x² - 2px + p²) + q  ← distribute parenthesis

= ax² - 2apx + ap² + q

Compare coefficients of x² term

a = 4

Compare coefficients of x- term

- 2ap = - 16, that is

- 2(4)p = - 16

- 8p = - 16 ( divide both sides by - 8 )

p = 2

Compare constant terms

ap² + q = 15 , that is

4(2)² + q = 15

16 + q = 15 ( subtract 16 from both sides )

q = - 1

Thus a = 4, p = 2, q = - 1

8 0
3 years ago
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