X + y = 22
x = 3y + 2
3y + 2 + y = 22
4y + 2 = 22
4y = 22 - 2
4y = 20
y = 20/4
y = 5
x = 3y + 2 = 3(5) + 2 = 15 + 2 = 17
ur numbers are 5 and 17
4+28= 32
Think of it as you have 28 apples and someone gave you 4 how many would you have
Answer:
l3-5 Is how you should write this.
Answer:
3003
Step-by-step explanation:
The number of differents menus containing 10 main courses that the restaurant can make if it has 15 main courses from which to chose is calculated through the combination: 15C10. The formula of the combination is: nCr = n! / ((r!) x(n - r)!)
Where r=10 and n=15
Substituting the values to the equation: 15C10 = 15! / (10!)x(10 - 5)! = 3003
Then there are 3003 different menus that a restaurant can makeif it has 15 main courses from which to choose.
The first one is B) september 10 but idk the second one
