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Softa [21]
3 years ago
15

Solve what is 1/2 x 15

Mathematics
1 answer:
Andreas93 [3]3 years ago
8 0

Answer:

7.5

Step-by-step explanation:

it's basically just 15 divided by 2

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Rashad has 24 jolly ranchers and 56 blow pops for making treat bags for his sisters birthday party. what is the largest number o
Vinil7 [7]

The largest numbers of snacks bag can be number 80 which consists of 24 jolly ranchers and 56 blow pops.

Given that Rashad has 24 jolly ranchers and 56 blow pops for making treat bags for his sister's birthday party and asked to find out the largest numbers of snacks in the bag.

There are 24 jolly ranchers and 56 blow pops and For the maximum numbers of snacks in the bag can be 24 jolly ranchers and 56 blow pops.

The maximum numbers of snacks that can be filled in a snacks bag is 24 jolly ranchers and 56 blow pops.

Therefore,The largest numbers of snacks bag can be number 80 which consists of 24 jolly ranchers and 56 blow pops.

Learn more about numbers here:

brainly.com/question/17429689

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7 0
1 year ago
Why was igor unhappy about his spelling test even though he got every thing right
Furkat [3]
Igor might've been unhappy because he cheated to get a good grade/score.
4 0
3 years ago
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Help! Read the question on the image! Thanks!
Vilka [71]

Answer:

its not A if your asking that

Step-by-step explanation:

i cant see all imeges but look you the one that has 1 as the x vaue and goes to 5 for the first plot.

6 0
3 years ago
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Which of the graphs below represents the equation 8x - y = -4?
vichka [17]
Well since you dont have the graphs posted i can tell u the y-intercept and the slope and you can figure it out from there.

8x-y=-4
-y=-8x-4
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4 0
3 years ago
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Point T is the midpoint of JH. The coordinate of T is (0, 5) and the coordinate of J is (0, 2). The coordinate of H is:
aev [14]
\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&J&(~ 0 &,& 2~) 
%  (c,d)
&H&(~ x &,& y~)
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)
\\\\\\
\left(\cfrac{x+0}{2}~~,~~\cfrac{y+2}{2}  \right)=\stackrel{midpoint~T}{(0~,~5)}\implies 
\begin{cases}
\cfrac{x+0}{2}=0\\\\
\boxed{x=0}\\
------\\
\cfrac{y+2}{2}=5\\\\
y+2=10\\
\boxed{y=8}
\end{cases}
6 0
3 years ago
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