2.36 is the answer because if you subtract 24.75 from 53.07 and then divide your answer by 12 is how you get your answer
Answer:
y = 3x - 10
Step-by-step explanation:
Starting with 3x - y = 10, add y to both sides:
3x = 10 + y
Then subtract 10 from both sides:
3x - 10 = y
If you switch the sides of the equation, it can also be written as:
y = 3x - 10
Answer:
y=4(5) =20
Step-by-step explanation:
Answer:
The dimension of the rug would be 17 ft × 9 ft.
Step-by-step explanation:
Given
length of the room = 27 ft.
width of the room = 19 ft.
suppose, she leaves a uniform strip of x ft. around the rug.
So,
The length of rug = (27-2x)ft.
Width of rug= (19-2x)ft.
∴ Area of the rug= length×width



According to the question,

( subtract 153 both sides)



( Middle term splitting)



or
( zero product property)
or 
if x=18, dimension would be negative ( Not possible)
Thus, x= 5
Hence,
length of rug= 27-10=17 ft.
width of rug= 19-10=9 ft.
The volume of a cuboid toy chest is equal to their product of the length,
width, and height.
- The correct option for the toy chest she should purchase is; <u>Only toy chest A will provide the necessary storage space</u>.
Reasons:
The dimensions of the toy chest are;
Toy chest A;
Length = 5 feet
Width = 4 feet
Height = 2 feet
Toy chest B;
Length = 4 feet
Width = 2 feet
Height = 4 feet
Volume of Toy chest A = 5 ft. × 4 ft. × 2 ft. = 40 ft.³
Volume of Toy chest B = 4 ft. × 2 ft. × 4 ft. = 32 ft.³
The volume of the toy chest Mrs. Smith needs = 35 ft.³
The toy chest Mrs. Smith should purchase is Toy chest A, that has a volume of 40 ft.³, which can store items that with a volume of 35 ft.³
The correct option is; <u>Only toy chest A will provide the necessary storage space</u>
<em>Possible question options obtained from a similar question found online are;</em>
<em>Either toy chest have the storage space needed</em>
<em>Neither has the storage space needed</em>
<em>Only toy chest A</em>
<em>Only toy chest B</em>
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Learn more about calculating volumes of various shapes here:
brainly.com/question/3789826